22. How many irreducible factors over over Q does x^48 - 1 have?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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ANSWER 22 only
21. Let K be the splitting field of x^23 - 1 over Q
and zeta 3 be a 23rd primitive root of unity.
Then what is order of the Galois group of K
over Q?
Enter your answer
22. How many irreducible factors over
over Q does x^48 - 1 have?
Enter your answer
23. The splitting field of f=(x^2-2)(x^2+1) over Q
is Q(sqrt(2),i) because its roots are sqrt(2),-
sqrt(2),i,-i. The Galois group of f contains the
following automorphisms: sigma o: sqrt(2) → -
sqrt(2) and tau T: i-i. Which subfield of the
splitting field is fixed by sigma?
Transcribed Image Text:21. Let K be the splitting field of x^23 - 1 over Q and zeta 3 be a 23rd primitive root of unity. Then what is order of the Galois group of K over Q? Enter your answer 22. How many irreducible factors over over Q does x^48 - 1 have? Enter your answer 23. The splitting field of f=(x^2-2)(x^2+1) over Q is Q(sqrt(2),i) because its roots are sqrt(2),- sqrt(2),i,-i. The Galois group of f contains the following automorphisms: sigma o: sqrt(2) → - sqrt(2) and tau T: i-i. Which subfield of the splitting field is fixed by sigma?
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