22. Heights of women. The heights of American women between the ages of 18 and 24 are approximatelynormally distributed. The mean is 64.1 inches, and the standard deviation is 2.5 inches. What percentage ofsuch women is over 5 feet 9 inches tall?2. Percent of women:nter answer as a percentage with percent sign, rounded to nearest whole percent, or as equivalent decimal or ratio.Submit

normal distributionμ = 64.1 inchesσ = 2.5 inchesP(height over 5 feet 9 inch) = ?

Answered: 22. Heights of women. The heights of…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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In the 1992 presidential election, Alaska's 40 election districts averaged 1993 votes per district for President Clinton. The standard deviation was 584. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( b. Is 1993 a population mean or a sample mean? Select an answer v C. Find the probability that a randomly selected district had fewer than 2053 votes for President Clinton. d. Find the probability that a randomly selected district had between 2074 and 2208 votes for President Clinton. e. Find the 95th percentile for votes for President Clinton. Round your answer to the nearest whole number.
A distribution has mean 100 and standard deviation 3. What is the largest percent of the data that is guaranteed to be between 40 and 160 93.75 96 97.44 99.75 99.99
the following numbers show the mileage of cars 10 sold . 86 , 87,90 , 87.2,88.2,87.4,87.8,89.7,88.9,89.6 find mean, standard deviation using probabilty plot. explain if data is normally distributed or not
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In the 1992 presidential election, Alaska's 40 election districts averaged 2038 votes per district for President Clinton. The standard deviation was 576. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(,)b. Is 2038 a population mean or a sample mean? Select an answer Population Mean Sample Mean c. Find the probability that a randomly selected district had fewer than 1842 votes for President Clinton. d. Find the probability that a randomly selected district had between 1997 and 2099 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.
What is the proportion that lies between the z scores under the normal curve? A. 1.00 and -1.00 B. 1.96 and -1.96 C. 2.58 and -2.58 D. 0.00 and 1.00 E. 1.50 and 0.10 F. 2.00 and 0.80
Electricity bills: According to a government energy agenCy 2011 was $110. 10. Assume the amounts are normally distributed with standard deviation $21.00. Use the TI-84 Plus calculator to answer the following. electricity bil in the United States in (a) Find the 7th percentile of the bill amounts. (b) Find the 58th percentile of the bill amounts. (c) Find the median of the bill amounts. Round the answers to at least two decimal places.
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state health web site provides information on the cost-to-charge ratio (the percentage of billed charges that are actual costs to the hospital). The cost-to-charge ratios for both inpatient and outpatient care in 2002 for a sample of six hospitals of that state follow. (Use a statistical computer package to calculate the P-value. Use ?inpatient − ?outpatient. Round your test statistic to two decimal places and your P-value to three decimal places.) Hospital 2002InpatientRatio 2002OutpatientRatio 1 86 78 2 77 58 3 99 77 4 65 57 5 65 50 6 104 69 t = df = P-value = Is there sufficient evidence to suggest that the mean difference cost-to-charge ratio for the state's hospitals is lower for outpatient care than for inpatient care? Use a significance level of 0.05. Yes OR No
Can you please help by providing the answer
n the 1992 presidential election, Alaska's 40 election districts averaged 2111 votes per district for President Clinton. The standard deviation was 551. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(,)b. Is 2111 a population mean or a sample mean? Select an answer Population Mean Sample Mean c. Find the probability that a randomly selected district had fewer than 2134 votes for President Clinton. d. Find the probability that a randomly selected district had between 2048 and 2241 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.
answer letter B using the above informations

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