22. Given the function f(x) = -2x²-16x-29, a) find the slope of the line tangent to the function at the point (-2,-5), then b) write the equation of the function in slope-intercept form. Tangent Slope: Equation of Tangent Line: Show Your Work 口

Q: the line parallel to -6x + ½y = 0 and passing through (10, 10)

A: Two parallel line have same gradient.

Q: a line perpendicular to y 5x-2 through (-10, 6) slope of the new line: equation:

A: Given, data is: A line is perpendicular to y=5x-2 through point -10,6

Q: Slope intercept through(2,-9) and (3,-14)

A:

Q: e equation y + 9 = 4(x - 2) in slope-interc

A: Explanation of the answer is as follows

Q: Function Slope Vertical Intercept Horizontal Intercept 10х + 9 y = 8 + 4x Y = 3x Y = – 3 x = - 2

A:

Q: Write the equation that defines two differentiable functions?

A: The functions which are differentiable in the defined limits are said to be a differentiable…

Q: Write the slope-intercept form of the line tangent to the curve f (x) = -2x³ – 6x² + 8 at the point…

A:

Q: How do I put this in point slope form and slope intercept form?m=-1 (-1/2, -2)

A: The general point slope form for the given slope m, and the point (x1, y1 ) is given as follows.