22. A solution of sodium sulfide reacts with 200. mL of 3.75 M HCl to form a solution of sodium chloride and hydrogen sulfide gas (H₂S). What volume of hydrogen sulfide is collected at STP?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
icon
Concept explainers
Question

Show work for it, please!

**Educational Content: Chemistry Problem Solving**

**Problem Statement:**

22. A solution of sodium sulfide reacts with 200. mL of 3.75 M HCl to form a solution of sodium chloride and hydrogen sulfide gas (H₂S). What volume of hydrogen sulfide is collected at STP?

**Analysis:**

This problem involves a stoichiometric calculation based on the reaction between sodium sulfide (Na₂S) and hydrochloric acid (HCl). The reaction produces sodium chloride (NaCl) and hydrogen sulfide gas (H₂S).

**Key Information:**
- Volume of HCl solution = 200. mL
- Molarity of HCl solution = 3.75 M
- Final product gases: H₂S
- Conditions: Standard Temperature and Pressure (STP), where 1 mole of any ideal gas occupies 22.4 L.

### Step-by-Step Solution:

1. **Balanced Chemical Equation:**
   The reaction between sodium sulfide and hydrochloric acid can be written as:
   \[
   Na₂S + 2HCl → 2NaCl + H₂S
   \]

2. **Moles of HCl:**
   Calculate the moles of HCl provided:
   \[
   Moles\ of\ HCl = Molarity \times Volume (in\ liters)
   \]
   \[
   Moles\ of\ HCl = 3.75\ M \times 0.200\ L = 0.75\ moles\ HCl
   \]

3. **Stoichiometry:**
   According to the balanced equation, 2 moles of HCl produce 1 mole of H₂S.
   
   Therefore, moles of H₂S produced:
   \[
   Moles\ of\ H₂S = \frac{moles\ of\ HCl}{2} = \frac{0.75}{2} = 0.375\ moles\ H₂S
   \]

4. **Volume of H₂S at STP:**
   At STP, 1 mole of gas occupies 22.4 liters. Thus,
   \[
   Volume\ of\ H₂S = moles\ of\ H₂S \times 22.4\ L/mol
   \]
   \[
   Volume\ of\ H₂S =
Transcribed Image Text:**Educational Content: Chemistry Problem Solving** **Problem Statement:** 22. A solution of sodium sulfide reacts with 200. mL of 3.75 M HCl to form a solution of sodium chloride and hydrogen sulfide gas (H₂S). What volume of hydrogen sulfide is collected at STP? **Analysis:** This problem involves a stoichiometric calculation based on the reaction between sodium sulfide (Na₂S) and hydrochloric acid (HCl). The reaction produces sodium chloride (NaCl) and hydrogen sulfide gas (H₂S). **Key Information:** - Volume of HCl solution = 200. mL - Molarity of HCl solution = 3.75 M - Final product gases: H₂S - Conditions: Standard Temperature and Pressure (STP), where 1 mole of any ideal gas occupies 22.4 L. ### Step-by-Step Solution: 1. **Balanced Chemical Equation:** The reaction between sodium sulfide and hydrochloric acid can be written as: \[ Na₂S + 2HCl → 2NaCl + H₂S \] 2. **Moles of HCl:** Calculate the moles of HCl provided: \[ Moles\ of\ HCl = Molarity \times Volume (in\ liters) \] \[ Moles\ of\ HCl = 3.75\ M \times 0.200\ L = 0.75\ moles\ HCl \] 3. **Stoichiometry:** According to the balanced equation, 2 moles of HCl produce 1 mole of H₂S. Therefore, moles of H₂S produced: \[ Moles\ of\ H₂S = \frac{moles\ of\ HCl}{2} = \frac{0.75}{2} = 0.375\ moles\ H₂S \] 4. **Volume of H₂S at STP:** At STP, 1 mole of gas occupies 22.4 liters. Thus, \[ Volume\ of\ H₂S = moles\ of\ H₂S \times 22.4\ L/mol \] \[ Volume\ of\ H₂S =
Expert Solution
steps

Step by step

Solved in 6 steps

Blurred answer
Knowledge Booster
Ideal and Real Gases
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY