Evaluate contour integrals 2+2-dz;z²(z - 1 - i)(a) || = 1,(b) | 2 - 1 - i = 1(5) f1foz³(z - 4)(a) || = 1,(b) | = 2 = 1=- dz;

Answered: 2+2 -dz; = z²(z-1-i) (a) || = 1, (b) |…

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter1: Fundamental Concepts Of Algebra

Section1.2: Exponents And Radicals

Problem 24E

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Question

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Evaluate contour integrals

2+2
-dz;
z²(z - 1 - i)
(a) || = 1,
(b) | 2 - 1 - i = 1
(5) f
1
fo
z³(z - 4)
(a) || = 1,
(b) | = 2 = 1
=
- dz;

Expert Solution

Step 1: ''Introduction to the solution''

5) a) Let $I subscript 1 equals integral subscript C fraction numerator z plus 2 over denominator z squared open parentheses z minus 1 minus i close parentheses end fraction d z comma space w h e r e space C colon space open vertical bar z close vertical bar equals 1$

$equals integral subscript C space fraction numerator g left parenthesis z right parenthesis over denominator z squared end fraction d z....... left parenthesis 1 right parenthesis space comma w h e r e space g left parenthesis z right parenthesis equals fraction numerator left parenthesis z plus 2 right parenthesis over denominator open parentheses z minus 1 minus i close parentheses end fraction space$

Cleary, g is analytic inside and on C.

Then, we can apply the Cauchy Integral theorem for the above integral.

Cauchy Integral's theorem: Let $f left parenthesis z right parenthesis$ be an analytic function inside and on a closed contour C and $alpha element of$ IntC, being the interior of C. Then, $f to the power of left parenthesis n right parenthesis end exponent left parenthesis alpha right parenthesis equals fraction numerator n factorial over denominator 2 pi i end fraction integral subscript C fraction numerator f left parenthesis z right parenthesis over denominator open parentheses z minus alpha close parentheses to the power of n plus 1 end exponent end fraction........ left parenthesis 2 right parenthesis comma n equals 0 comma 1 comma 2 comma......$

Then, $integral subscript C space fraction numerator g left parenthesis z right parenthesis over denominator z squared end fraction d z equals fraction numerator 2 pi i over denominator 1 factorial end fraction. g apostrophe left parenthesis 0 right parenthesis equals space 2 pi i cross times g apostrophe left parenthesis 0 right parenthesis......... left parenthesis 3 right parenthesis$

Now, $g apostrophe left parenthesis z right parenthesis equals fraction numerator left parenthesis z minus 1 minus i right parenthesis left parenthesis 1 right parenthesis minus left parenthesis z plus 2 right parenthesis left parenthesis 1 right parenthesis over denominator open parentheses z minus 1 minus i close parentheses squared end fraction equals fraction numerator negative left parenthesis 3 plus i right parenthesis over denominator open parentheses z minus 1 minus i close parentheses squared end fraction$

$rightwards double arrow g to the power of apostrophe open parentheses 0 close parentheses equals negative fraction numerator open parentheses 3 plus i close parentheses over denominator open parentheses 1 plus i close parentheses squared end fraction equals negative fraction numerator open parentheses 3 plus i close parentheses over denominator left parenthesis 1 minus 1 plus 2 i right parenthesis end fraction equals negative fraction numerator left parenthesis 3 plus i right parenthesis over denominator 2 i end fraction equals negative 1 half open parentheses 1 plus 3 over i close parentheses equals negative 1 half open parentheses 1 minus 3 i close parentheses equals fraction numerator left parenthesis 3 i minus 1 right parenthesis over denominator 2 end fraction$

Now,using this value in (3), we get, $integral subscript C space fraction numerator g left parenthesis z right parenthesis over denominator z squared end fraction d z equals fraction numerator left parenthesis 3 i minus 1 right parenthesis over denominator 2 end fraction cross times 2 straight pi straight i equals straight pi straight i left parenthesis 3 straight i minus 1 right parenthesis$

(b) Let $I subscript 2 equals integral subscript C space fraction numerator f left parenthesis z right parenthesis over denominator open parentheses z minus 1 minus i close parentheses end fraction d z comma space w h e r e space f left parenthesis z right parenthesis equals fraction numerator left parenthesis z plus 2 right parenthesis over denominator left parenthesis z minus 1 minus i right parenthesis end fraction comma space$ being analytic inside and on C: $open vertical bar z minus left parenthesis 1 plus i right parenthesis close vertical bar equals 1$

Then, by Cauchy's Integral theorem, $I subscript 2 equals 2 straight pi straight i cross times straight f left parenthesis 1 plus straight i right parenthesis equals 2 straight pi straight i cross times fraction numerator left parenthesis 1 plus straight i plus 2 right parenthesis over denominator open parentheses 1 plus straight i close parentheses squared end fraction equals straight pi left parenthesis 3 plus straight i right parenthesis$

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2+2 -dz; = z²(z-1-i) (a) || = 1, (b) | - 1 - i = 1 (5) f 1 fc = 23 ( 2 - 4) (a) | = 1, (b) |z – 2 = 1 -dz;