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- State which of the following compounds is/are aromatic and non-aromatic? Classify the compounds based on Hückel's Rule by providing their n values. II II IVIs the following molecule/compound aromatic or not aromatic? Choose the correct answer (and motive) from options provided ( ZI O It has 10 T aelectrons, therefore aromatic It has 6 m electrons and satisfy Hückel's rule, therefore aromatic O is not aromatic because it has 10 m electrons and does not satisfy Huckel's rule for aromatic compounds O It has 8 mr electrons, and therefore aromaticis this molecule aromatic ,anti aromoatic,or non aromatic??
- What is the main difference between an aromatic and an anti-aromatic compound? O None of these O Aromatic compounds must satisfy Hückel's rule. O Anti-aromatic compounds must have a conjugated system with a p orbital at every vertex. O Aromatic compounds must be cyclic and planar but not anti-aromatic compounds. O Aromatic compounds must be monocyclic.Tell which of the following compounds is aromatic and which one is antiaromatic or non-aromatic.Which structure is not aromatic? 90 do 0
- Categorize the following molecules as aromatic, anti-aromatic, or non-aromatic by adding the assigned letters to the corresponding category. Assume each molecule is planar.Which structure is NOT aromatic? H,CWhich one of the following statements from Chapter 8 and 18 is FALSE? O For a compound to be classified as aromatic, it must have an odd number of pairs of n-electrons and must be fully conjugated, cyclic and planar. O Inclusion of heteroatoms as part of the conjugated ring system renders the molecule to be considered non-aromatic. O Benzene is a six-membered ring where the n-electrons are equally shared across all six carbons in the ring and thus it possesses 36 kcal/mol of resonance stabilization energy. O The key reaction in Chapter 18 is the EAS reaction, which stands for electrophilic aromatic substitution. O All EAS reactions follow the same three mechanistic steps: (1) generate the electrophile, (2) capture the electrophile to give a carbocation intermediate, and (3) loss of a proton to regain aromaticity.