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22) and y. a.x=16;y=853 6. x=852;y=452 C.x = 8√3; y = 16 d. x = 8√√2;y=853 See the diagram. Solve for x + y

22) and y. a.x=16;y=853 6. x=852;y=452 C.x = 8√3; y = 16 d. x = 8√√2;y=853 See the diagram. Solve for x + y

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please answer #22
**Question 22: See the diagram. Solve for x and y.** **Options:** a. \( x = 16 \); \( y = 8\sqrt{3} \) b. \( x = 8\sqrt{2} \); \( y = 4\sqrt{2} \) c. \( x = 8\sqrt{3} \); \( y = 16 \) d. \( x = 8\sqrt{2} \); \( y = 8\sqrt{3} \) **Diagram Description:** The diagram provided is a right triangle. The triangle has one angle labeled as \( 60^\circ \), a right angle (\( 90^\circ \)), and one side labeled "8" (the length of the side opposite the \( 60^\circ \) angle). The sides of the triangle are labeled as follows: the side opposite the \( 60^\circ \) angle is labeled "8", the side adjacent to the \( 60^\circ \) angle is labeled "x," and the hypotenuse is labeled "y".
Transcribed Image Text:**Question 22: See the diagram. Solve for x and y.** **Options:** a. \( x = 16 \); \( y = 8\sqrt{3} \) b. \( x = 8\sqrt{2} \); \( y = 4\sqrt{2} \) c. \( x = 8\sqrt{3} \); \( y = 16 \) d. \( x = 8\sqrt{2} \); \( y = 8\sqrt{3} \) **Diagram Description:** The diagram provided is a right triangle. The triangle has one angle labeled as \( 60^\circ \), a right angle (\( 90^\circ \)), and one side labeled "8" (the length of the side opposite the \( 60^\circ \) angle). The sides of the triangle are labeled as follows: the side opposite the \( 60^\circ \) angle is labeled "8", the side adjacent to the \( 60^\circ \) angle is labeled "x," and the hypotenuse is labeled "y".
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