Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
100%
How would I go about calculating the surface area?
![### Question 22: Surface Area of a Sphere
#### Problem Statement
A sphere with a radius (r) of 4 cm is given. Calculate the surface area of the sphere.
#### Diagram
The diagram provided shows a sphere with a labeled radius. The radius is indicated as a line extending from the center of the sphere to its surface. The sphere is simply labeled as "a sphere."
#### Options
- A) 67.0 cm²
- B) 200.8 cm²
- C) 267.9 cm²
- D) 50.2 cm²
#### Explanation
To solve this problem, you will use the formula for the surface area of a sphere:
\[ \text{Surface Area} = 4 \pi r^2 \]
Given:
- Radius \( r = 4 \, \text{cm} \)
- \(\pi \approx 3.14\)
Step-by-Step Solution:
1. Calculate \( r^2 \):
\[ r^2 = 4^2 = 16 \, \text{cm}^2 \]
2. Multiply by \(\pi\):
\[ 4 \pi r^2 = 4 \times 3.14 \times 16 \]
3. Simplify the multiplication:
\[ 4 \times 3.14 = 12.56 \]
\[ 12.56 \times 16 = 200.96 \, \text{cm}^2 \]
The closest option to 200.96 cm² is:
- **B) 200.8 cm²**
Thus, the answer is **B) 200.8 cm²**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff8311114-a7cb-49e3-b44e-1e05de4bc29a%2F48034c2f-7a3a-4d13-8d30-de9c7401df57%2Fdygo33r.png&w=3840&q=75)
Transcribed Image Text:### Question 22: Surface Area of a Sphere
#### Problem Statement
A sphere with a radius (r) of 4 cm is given. Calculate the surface area of the sphere.
#### Diagram
The diagram provided shows a sphere with a labeled radius. The radius is indicated as a line extending from the center of the sphere to its surface. The sphere is simply labeled as "a sphere."
#### Options
- A) 67.0 cm²
- B) 200.8 cm²
- C) 267.9 cm²
- D) 50.2 cm²
#### Explanation
To solve this problem, you will use the formula for the surface area of a sphere:
\[ \text{Surface Area} = 4 \pi r^2 \]
Given:
- Radius \( r = 4 \, \text{cm} \)
- \(\pi \approx 3.14\)
Step-by-Step Solution:
1. Calculate \( r^2 \):
\[ r^2 = 4^2 = 16 \, \text{cm}^2 \]
2. Multiply by \(\pi\):
\[ 4 \pi r^2 = 4 \times 3.14 \times 16 \]
3. Simplify the multiplication:
\[ 4 \times 3.14 = 12.56 \]
\[ 12.56 \times 16 = 200.96 \, \text{cm}^2 \]
The closest option to 200.96 cm² is:
- **B) 200.8 cm²**
Thus, the answer is **B) 200.8 cm²**.
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.Recommended textbooks for you

Algebra and Trigonometry (6th Edition)
Algebra
ISBN:
9780134463216
Author:
Robert F. Blitzer
Publisher:
PEARSON

Contemporary Abstract Algebra
Algebra
ISBN:
9781305657960
Author:
Joseph Gallian
Publisher:
Cengage Learning

Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning

Algebra and Trigonometry (6th Edition)
Algebra
ISBN:
9780134463216
Author:
Robert F. Blitzer
Publisher:
PEARSON

Contemporary Abstract Algebra
Algebra
ISBN:
9781305657960
Author:
Joseph Gallian
Publisher:
Cengage Learning

Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning

Algebra And Trigonometry (11th Edition)
Algebra
ISBN:
9780135163078
Author:
Michael Sullivan
Publisher:
PEARSON

Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:
9780980232776
Author:
Gilbert Strang
Publisher:
Wellesley-Cambridge Press

College Algebra (Collegiate Math)
Algebra
ISBN:
9780077836344
Author:
Julie Miller, Donna Gerken
Publisher:
McGraw-Hill Education