(22 – 2) | Evaluate dx 2+2 (x4+5x2 +4) tan1 2 A - BI E E E E X O Type here to search 马

Q: Evaluate √x/2 6sinx(cosx+1) do

A:

Q: gien oferdone (D- JI) (D +3I); the to the grven finctions e-3%

A: (D-2I)(D+3I)=D2+3D-2D-6I=D2+D-6I Apply the operator on e2x…

Q: S(1 + sinx)-1sinxdx

A:

Q: Evaluate fa tan() da 1 글 [(22 + 2a) tan-1 ()-피+C o b을[(22+ 2a) tan-1 () + z] +C 2a) tan-1 ()- 피 +C…

A: Solve the above integration.

Q: 3 2.)f x³ (4 + x²)² dx ; Use rationalizing substitution

A:

Q: oB coser sec 2o -

A: To find the value of 2cosec20°sec20°

Q: tan(2 – j5) j(2-j5) +7- jv2 In(-5)| (3220° – sin 20 + jln5)*|

A:

Q: Evaluate: 3 f(-x² + 4x-1)dx 1

A:

Q: Evaluate tan (7x +1) sec³(7x +

A: Given that: ∫tan5(7x+1).sec3(7x+1)dx

Q: 4, 8 sec3x tan5x dx

A:

Q: 1. (a) Determine + 2x2 dx (b) Determine + 2x2 dx

A:

Q: , 8 tan² (2x) dx

A:

Q: S sec² (7t) tan² (7t) √1 – tan² (7t) dt

A: Given integral:- ∫sec27ttan27t1-tan27tdt

Q: 2 X 2 X 0+ - 4 +4 dx =

A: C+C

Q: 07 tanxtan2x + tan2xtan3x +. + tan5xtan6x-D14 tan6x calculate: tan x 15 10 20

A: It is known that tanA-B=tanA-tanB1+tanAtanB.

Q: Find a suitable substitution for evaluating ∫tan x sec2 x dx andexplain your choice.

A: we have to integrate the following integral using a suitable substitution. ∫tanx.sec2xdx

Q: (tan 4x + sec 3x) dx

A: Answer is mentioned below

Q: хt — х +6 dx х3 + Зх

A: We shall use polynomial long division method to simplify our integrand.

Q: Q. / 3sec3xtan3xdx sec3x +c -sec3x +c O None O tan3x +oс

A:

Q: Evaluate V1-x-dx A. --(x+xvI– x-) +C B. (x+xV1%3=x) +C c. (x+xv1+x-) +C D. -(x-xVT-x-) + C xv1-x)+ C

A: Find your answer below

Q: Evaluate G r. d.x. (x2+1)(x+1) 0.

A: The following integrals are useful, while evaluating the integral that is provided. ∫dxx =ln x +C…

Q: Evaluate J sec3x cosecx dx

A: