21t2. Write a function f Suppose y = 3t + 5 and x = that determines y in terms of x. (Assume t > 0.) f(x) Preview

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Suppose \( y = 3t + 5 \) and \( x = 21t^2 \). Write a function \( f \) that determines \( y \) in terms of \( x \). (Assume \( t \geq 0 \).)

**Solution:**

To express \( y \) as a function of \( x \), follow these steps:

1. **Solve for \( t \)** using the equation \( x = 21t^2 \):

   \[
   t^2 = \frac{x}{21}
   \]

2. **Express \( t \)** in terms of \( x \) by taking the square root, considering \( t \geq 0 \):

   \[
   t = \sqrt{\frac{x}{21}}
   \]

3. **Substitute \( t \)** in the equation \( y = 3t + 5 \) to express \( y \) in terms of \( x \):

   \[
   y = 3\left(\sqrt{\frac{x}{21}}\right) + 5
   \]

Thus, the function \( f(x) \) that determines \( y \) in terms of \( x \) is:

\[
f(x) = 3\sqrt{\frac{x}{21}} + 5
\]
Transcribed Image Text:**Problem Statement:** Suppose \( y = 3t + 5 \) and \( x = 21t^2 \). Write a function \( f \) that determines \( y \) in terms of \( x \). (Assume \( t \geq 0 \).) **Solution:** To express \( y \) as a function of \( x \), follow these steps: 1. **Solve for \( t \)** using the equation \( x = 21t^2 \): \[ t^2 = \frac{x}{21} \] 2. **Express \( t \)** in terms of \( x \) by taking the square root, considering \( t \geq 0 \): \[ t = \sqrt{\frac{x}{21}} \] 3. **Substitute \( t \)** in the equation \( y = 3t + 5 \) to express \( y \) in terms of \( x \): \[ y = 3\left(\sqrt{\frac{x}{21}}\right) + 5 \] Thus, the function \( f(x) \) that determines \( y \) in terms of \( x \) is: \[ f(x) = 3\sqrt{\frac{x}{21}} + 5 \]
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