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218.38.54.72.11.13-17-19 How many zeros are at the end of (201)2 when it is written in decimal form? Fill in the blanks below to show how to use the result of part (b) to answer this question. By the result of part (b), (20!) has factors of 2 and When (20!)2 is written in decimal form, each zero at its end comes from one factor of 2 together with one factor of . Thus, (201)2 has factors of 2 and factors of factors of , which implies that when (20!)2 is written in ordinary decimal form, it ends with zeros.

218.38.54.72.11.13-17-19 How many zeros are at the end of (201)2 when it is written in decimal form? Fill in the blanks below to show how to use the result of part (b) to answer this question. By the result of part (b), (20!) has factors of 2 and When (20!)2 is written in decimal form, each zero at its end comes from one factor of 2 together with one factor of . Thus, (201)2 has factors of 2 and factors of factors of , which implies that when (20!)2 is written in ordinary decimal form, it ends with zeros.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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218.38.54.72.11.13-17-19 How many zeros are at the end of (201)2 when it is written in decimal form? Fill in the blanks below to show how to use the result of part (b) to answer this question. By the result of part (b), (20!) has factors of 2 and When (20!)² is written in decimal form, each zero at its end comes from one factor of 2 together with one factor of J. Thus, (201)2 has factors of 2 and factors of factors of , which implies that when (20!)2 is written in ordinary decimal form, it ends with zeros.
Transcribed Image Text:218.38.54.72.11.13-17-19 How many zeros are at the end of (201)2 when it is written in decimal form? Fill in the blanks below to show how to use the result of part (b) to answer this question. By the result of part (b), (20!) has factors of 2 and When (20!)² is written in decimal form, each zero at its end comes from one factor of 2 together with one factor of J. Thus, (201)2 has factors of 2 and factors of factors of , which implies that when (20!)2 is written in ordinary decimal form, it ends with zeros.
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