215. A uniform concrete slab of total weight W is to be attached, as shown in Fig. P-215, to two rods whose lower ends are on the same level. Determine the ratio of the areas of the rods so that the slab will remain level. Ans. A/A = 3.87 %3D Aluminum E = 10 X 106 psi L = 4 ft Steel E = 29 X 106 psi L = 6 ft Total Weight W 3 ft 6 ft- Figure P-215 1 ft

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A uniform concrete of total slab weight is to be attached, as show in Fig. P-215, to two rods whose lower ends are on the same level. Determie the ratios of the areas of the rods so that the slab will remain level.

 

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215. A uniform concrete slab of total weight W is to be attached, as shown in Fig.
P-215, to two rods whose lower ends are on the same level. Determine the ratio of
the areas of the rods so that the slab will remain level.
Ans.
Aa/A = 3.87
Steel
E = 29 X 106 psi
L = 6 ft
Aluminum
E = 10 x 106
L = 4 ft
psi
Total Weight = W
3 ft 6 ft-
Figure P-215
1 ft
11:40 AM
P Type here to search
O G ENG
16/3/2021
Transcribed Image Text:My Questions | bartleby A Messenger f 159082127_481326646520269_4 x M Inbox (18) - viacaguete@gmail.cc X A z-p3-scontent.fmnl3-4.fna.fbcdn.net/v/t1.15752-9/159082127_481326646520269_4704350368947155712_n.jpg?_nc_cat=102&ccb=D1-3&_nc_sid=ae9488&_nc_eui2=Ae. 215. A uniform concrete slab of total weight W is to be attached, as shown in Fig. P-215, to two rods whose lower ends are on the same level. Determine the ratio of the areas of the rods so that the slab will remain level. Ans. Aa/A = 3.87 Steel E = 29 X 106 psi L = 6 ft Aluminum E = 10 x 106 L = 4 ft psi Total Weight = W 3 ft 6 ft- Figure P-215 1 ft 11:40 AM P Type here to search O G ENG 16/3/2021
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