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21.68: A -3.00 nC point charge is on the x- axis at x = 1.20 m. A second point charge, Q, is on the x-axis at -0.600 m. What must be the sign and magnitude of Q for the resultant electric field at the origin to be (a) 45.0 N/C in the +x-direction, (b) 45.0 N/C in the -x- %3D direction?

21.68: A -3.00 nC point charge is on the x- axis at x = 1.20 m. A second point charge, Q, is on the x-axis at -0.600 m. What must be the sign and magnitude of Q for the resultant electric field at the origin to be (a) 45.0 N/C in the +x-direction, (b) 45.0 N/C in the -x- %3D direction?

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21.68: A -3.00 nC point charge is on the x- axis at x = 1.20 m. A second point charge, Q, is on the x-axis at -0.600 m. What must be the sign and magnitude of Q for the resultant electric field at the origin to be (a) 45.0 N/C in the +x-direction, (b) 45.0 N/C in the -x- direction?
Transcribed Image Text:21.68: A -3.00 nC point charge is on the x- axis at x = 1.20 m. A second point charge, Q, is on the x-axis at -0.600 m. What must be the sign and magnitude of Q for the resultant electric field at the origin to be (a) 45.0 N/C in the +x-direction, (b) 45.0 N/C in the -x- direction?
21.13: Three point charges are arranged on a line. Charge q3 = +5.00 nC and is at the origin. Charge q2 = -3.00 nC and is at x = +4.00 cm. Charge q1 is at x = +2.00 cm. What is q1 (magnitude and sign) if the net force on 93 is zero? %3D 21.35: A +2.00 nC point charge is at the origin, and a second -5.00 nC point charge is on the x-axis at x = 0.800 m. (a) Find the electric field (magnitude and direction) at each of the following points on the x-axis: (i) x = 0.200 m; (ii) x = 1.20 m; (iii) x = -0.200 m. (b) Find the net electric force that the two charges would exert on an electron placed at each point in part (a). 21.40: Point charge q1 = -5.00 nC is at the origin and point charge q2 = +3.00 nC is on %3D the x-axis at x = 3.00 cm. Point P is on the y- axis at y = 4.00 cm. (a) Calculate the electric fields Ej and E2 at point P due to the charges %3D 91 and q2 . Express your results in terms of unit vectors. (b) Use the results of part (a) to obtain the resultant field at P, expressed in unit vector form.
Transcribed Image Text:21.13: Three point charges are arranged on a line. Charge q3 = +5.00 nC and is at the origin. Charge q2 = -3.00 nC and is at x = +4.00 cm. Charge q1 is at x = +2.00 cm. What is q1 (magnitude and sign) if the net force on 93 is zero? %3D 21.35: A +2.00 nC point charge is at the origin, and a second -5.00 nC point charge is on the x-axis at x = 0.800 m. (a) Find the electric field (magnitude and direction) at each of the following points on the x-axis: (i) x = 0.200 m; (ii) x = 1.20 m; (iii) x = -0.200 m. (b) Find the net electric force that the two charges would exert on an electron placed at each point in part (a). 21.40: Point charge q1 = -5.00 nC is at the origin and point charge q2 = +3.00 nC is on %3D the x-axis at x = 3.00 cm. Point P is on the y- axis at y = 4.00 cm. (a) Calculate the electric fields Ej and E2 at point P due to the charges %3D 91 and q2 . Express your results in terms of unit vectors. (b) Use the results of part (a) to obtain the resultant field at P, expressed in unit vector form.
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