Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
can you help me solve number 21?

Transcribed Image Text:17. Sulfur is an element therefor it is nonpolar (and a non i-1
electrolyte). Carbon tetrachloride is a nonpolar solvent. Since
like dissolves like, these two are soluble. Use the simulation to
dissolve 5g of Sx in 100.g CC14 and note the freezing point.
Although the simulation only has 1 sig fig, let's pretend the 5g
S is 5.0g S and therefor 2 sig figs.
Tp = -28.55
-22,99
- 28. 55
S.56
Sulfur forms multiple allotropes (look it up\if you need to), like S6 and Sg. Use the process
below to identify which one we are working with.
18. Use the freezing point to calculate the molality of the solution.
Ms =
5.56
(1) (30)
AT
= 0.185
0,185
19. Use the molality and mass of solvent to find moles of S.
mol S="mcla9lity X Kg Solvent
= O. 1857 X 0.1g ccl4
Moles S:
0.0 185
20. Use the grams of S and moles of S to find the molar mass of
Molar mass of
the allotrope. 5.09 oais mel s=2.70 %mol
-270mol
mol S
allotrope: 270
0,0185
21. What is the formula of the allotrope of sulfur we are working
with (round to a whole number)
|cS
Formula of
allotrope:
Scanne
er
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