I need help understanding how A is the correct answer for problem 21 and B is the correct answer for problem 22. Please explain to me the procedure to get these answers. Thank you. ### Image Transcription for Educational Website#### Problems**21.** How many total cubic yards of coarse aggregate would be required to produce 150 yd³ of concrete if the coarse aggregate has a nominal size of 2.0 inch and a Fineness Modulus of 2.90?- A. 110- B. 0.73- C. 75- D. 150**Answer: A****22.** If 280 lb/yd³ of water is used in an air-entrained concrete mix with a coarse aggregate having a nominal aggregate size of 0.75 inches, which of the following would most likely be the slump of the concrete?- A. zero- B. 1.5 inch- C. 3.5 inch- D. 6.5 inch#### Relevant Tables and Equations:**Table 7.5** - Bulk Volume of Coarse Aggregate per Unit Volume of Concrete| Nominal Maximum Size of Aggregate, mm (in.) | 2.40 | 2.60 | 2.80 | 3.00 || --- | --- | --- | --- | --- || 9.5 (3/8) | 0.50 | 0.48 | 0.46 | 0.44 || 12.5 (1/2) | 0.59 | 0.57 | 0.55 | 0.53 || 19 (3/4) | 0.66 | 0.64 | 0.62 | 0.60 || 25 (1) | 0.70 | 0.68 | 0.67 | 0.65 || 37.5 (1 1/2) | 0.75 | 0.73 | 0.71 | 0.69 || 50 (2) | 0.78 | 0.76 | 0.74 | 0.72 || 75 (3) | 0.82 | 0.80 | 0.78 | 0.76 || 150 (6) | 0.87 | 0.85 | 0.83 | 0.81 |**Equation for % Volumetric Solids:**\[\% V_s = \left

Problem 21 : Data given Concrete to be produced = 150 yd3 Nominal size of coarse aggregates = 2 in Fineness modulus = 2.9 Find: Cubic yards of coarse aggregates required to produce 150 yd3 of concrete Solution Use the chart to find the bulk volume of dry rodded coarse aggregate per unit volume of concrete: Fineness modulus = 2.9, which is not there in the chart, so interpolate between 2.8 and 3 to get the value of 2.9. Nominal size of coarse aggregates = 2 in So for 2 in size, and Fineness modulus of 2.8, bulk volume of dry rodded coarse aggregate = 0.74 yd3 for 2 in size, and Fineness modulus of 3, bulk volume of dry rodded coarse aggregate = 0.72 yd3 From interpolation, value of bulk volume of dry rodded coarse aggregate, for Fineness modulus of 2.9 is: y-y1 = y2-y1x2-x1(x-x1) (y - 0.74) = 0.72-0.743-2.8(2.9-2.8) y =0.73 yd3 For 1 yd3 of concrete, bulk volume of dry rodded coarse aggregate required = 0.73 yd3 So for 150 yd3 concrete, bulk volume of dry rodded coarse aggregate required = 0.73×150 yd3 = 109.5 yd3 ≅110 yd3 Bulk volume of dry rodded coarse aggregate required = 110 yd3Problem 22 : Data given Water used = 280 lb/yd3 Nominal size of coarse aggregates = 0.75 in Find : Slump of concrete Solution Here the concrete is Air entrained, so use the chart of air entrained. From the chart above, Nominal maximum aggregate size of 0.75 in, and Mixing water quantity of 280 lb/yd3 , Slump of concrete should be between (1-2) in So take the average value = 1.5 in Slump of concrete = 1.5 in