Please show all calculations and type them out since I have bad eyesight and it is very difficult for me to read handwriting ### Heat Required to Raise the Temperature of Lead**Problem Statement:**How much heat is required to raise the temperature of a 225-g lead ball from 15.0°C to 25.0°C? The specific heat of lead is 128 J/(kg·K).**Multiple Choice Answers:**A) 725 J B) 576 J C) 217 J D) 288 J E) 145 J **Step-By-Step Solution:**To solve this problem, we use the formula for heat transfer:\[ Q = mcΔT \]Where:- \( Q \) is the heat required (in joules, J)- \( m \) is the mass (in kilograms, kg)- \( c \) is the specific heat capacity (in joules per kilogram per kelvin, J/(kg·K))- \( ΔT \) is the change in temperature (in degrees Celsius or Kelvin, as \( 1°C = 1 K \))1. **Convert the mass from grams to kilograms:**\[ 225\,g = 0.225\,kg \]2. **Specific heat capacity of lead:**\[ c = 128\,J/(kg·K) \]3. **Change in temperature:**\[ ΔT = 25.0°C - 15.0°C = 10.0\,K \]4. **Calculate the heat required:**\[ Q = (0.225\,kg) \times (128\,J/(kg·K)) \times (10.0\,K) \]\[ Q = 288\,J \]Thus, the heat required to raise the temperature of the lead ball is 288 J.**Correct answer:**D) 288 J

Given: Mass of lead m=225 g, Initial temperature Ti=15°C, Final temperature Tf=25°C, Specific heat…

Answered: 21) How much heat is required to raise…

21) How much heat is required to raise the temperature of a 225-g lead ball from 15.0°C to 25.0°C? The specific heat of lead is 128 J/kg.K. A) 725 J B) 576 J C) 217J D) 288 J E) 145 J

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter18: Temperature

Section: Chapter Questions

Problem 1P

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Calorimetry

Measuring the heat transferred during chemical reactions or other physical processes is known as calorimetry. It comes under the branch of thermochemistry.

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Please show all calculations and type them out since I have bad eyesight and it is very difficult for me to read handwriting

### Heat Required to Raise the Temperature of Lead

**Problem Statement:**
How much heat is required to raise the temperature of a 225-g lead ball from 15.0°C to 25.0°C? The specific heat of lead is 128 J/(kg·K).

**Multiple Choice Answers:**
A) 725 J
B) 576 J
C) 217 J
D) 288 J
E) 145 J

**Step-By-Step Solution:**

To solve this problem, we use the formula for heat transfer:

\[ Q = mcΔT \]

Where:
- \( Q \) is the heat required (in joules, J)
- \( m \) is the mass (in kilograms, kg)
- \( c \) is the specific heat capacity (in joules per kilogram per kelvin, J/(kg·K))
- \( ΔT \) is the change in temperature (in degrees Celsius or Kelvin, as \( 1°C = 1 K \))

1. **Convert the mass from grams to kilograms:**
\[ 225\,g = 0.225\,kg \]

2. **Specific heat capacity of lead:**
\[ c = 128\,J/(kg·K) \]

3. **Change in temperature:**
\[ ΔT = 25.0°C - 15.0°C = 10.0\,K \]

4. **Calculate the heat required:**
\[ Q = (0.225\,kg) \times (128\,J/(kg·K)) \times (10.0\,K) \]
\[ Q = 288\,J \]

Thus, the heat required to raise the temperature of the lead ball is 288 J.

**Correct answer:**
D) 288 J

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