20x"(t) + 140x'(t) + 200x(t) = 0 --> initial problem x(t) = (1/12)e^-2t + (1/6)e^-5t --> solution x(0) = .25 m x'(0) = -1 m/s When will it return to equilibrium? t = ?
20x"(t) + 140x'(t) + 200x(t) = 0 --> initial problem x(t) = (1/12)e^-2t + (1/6)e^-5t --> solution x(0) = .25 m x'(0) = -1 m/s When will it return to equilibrium? t = ?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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20x"(t) + 140x'(t) + 200x(t) = 0 --> initial problem
x(t) = (1/12)e^-2t + (1/6)e^-5t --> solution
x(0) = .25 m
x'(0) = -1 m/s
When will it return to equilibrium? t = ?
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