20358520 ealt, what is the probability that they form a straight ave sequential values, assume that Ace is high only
20358520 ealt, what is the probability that they form a straight ave sequential values, assume that Ace is high only
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Related questions
Question
![137
2. Start with a standard, well shuffled deck of 52 cards. For this question you may leave
your answers as expressions with combinations, factorials, fractions etc.
a. If 6 cards are dealt, what is the probability that there are exactly 3 unique pairs?
ex: [2,2,3,3,4,4,] but not [2,2,2,2,3,3]
(77) = 20358520
300000 (0)(zzo) (4) (4) (4)
( 52
20358520
= 0,00899
b. If 5 cards are dealt, what is the probability that they form a straight from the same
suit (all cards have sequential values, assume that Ace is high only, so Q<K<
A)?
c. If 7 cards are dealt, what is the probability of having 2 cards each from 3 of the
suits and one card from 1 of the suits?
(PC2S
49300
= 4.1045 x 1.4
=
(3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8d65aaa5-5279-4ebf-b541-f161ae051282%2Fa1e9743c-f160-4826-a262-3a08375e01ae%2Fpuai259_processed.jpeg&w=3840&q=75)
Transcribed Image Text:137
2. Start with a standard, well shuffled deck of 52 cards. For this question you may leave
your answers as expressions with combinations, factorials, fractions etc.
a. If 6 cards are dealt, what is the probability that there are exactly 3 unique pairs?
ex: [2,2,3,3,4,4,] but not [2,2,2,2,3,3]
(77) = 20358520
300000 (0)(zzo) (4) (4) (4)
( 52
20358520
= 0,00899
b. If 5 cards are dealt, what is the probability that they form a straight from the same
suit (all cards have sequential values, assume that Ace is high only, so Q<K<
A)?
c. If 7 cards are dealt, what is the probability of having 2 cards each from 3 of the
suits and one card from 1 of the suits?
(PC2S
49300
= 4.1045 x 1.4
=
(3)
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
Recommended textbooks for you
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON