2014. (₁) flts = < ² (0s 24, 2sinzt, 2+> filt = <- bsinzt, 6 cos 2+, 3> Are Length 2 = 0 X7, > 36s1u2+36 cas ² 6 + +9 3√5 dt ₂ 36 +9 = (+²+3) ² 355 (2) 45 = (1) flos = < (1²+1) cost, (+²+1) sint, 2√2+> [0, 1] f'(t) = < 2+ cost = (+²+1) sint, 2+sint + (+²+1) cost, 25₂) [[5 "(+1)] = [ (2 + rus+ - (²+1) sint) + (2+ siut + (+²+1) ceat)ª + (252) ² 24th utros't +²+1) 'sin't - Yt last sint (1²+1) + Page No. 4 + ² + ( + ² + 1)² + 3. | 4 + ² + + ² + 2 + ² + 2 + 8 = +² +6+² +9 = 3√5 315 म 2 4+²siv't + (+²+1) ² co²+ + 4 + + ² tusinf lost +8 = T (+²+ ²) 2+ = (+ ² + ²+ ] " + ( + + ³) = 2 Jo TO 3 4 Date <2 cos3t, 2sinst, 2+½> f'(M = < 6 sinst, 6 cosst, 2x² + > f'(t) = <- 6s²u²t, 6coszt 2+¼/2) 11 f'(+))) = ( 6 5²4²4 ) ² + (Gros ²4) ² + . O = fas 0 2 36 sin 34 +26cos ²2+ +9+ 36+9+ 3√√++4 dt = F₂ = J 1 31₂ - 4 ((1+1)^² + 2) = ² | (5) ²2² - ( 1³2 ) 4) 2 0 2 555 - 8) = 1055 -16 f(t) = < 2cus 2t, 2 sinzt, 3+> f'(t) = <- 6sinzt, 6Coszt, 33 Jo 3J++4 ||| f '(x) || = ²8 s³u²2+ + 36 cos ²2+ + 9 = L 3√5 + of Jt tu dt 355 dt first find the fre length function. it L(H = 355+ [0,1] 7 J45 2 355
2014. (₁) flts = < ² (0s 24, 2sinzt, 2+> filt = <- bsinzt, 6 cos 2+, 3> Are Length 2 = 0 X7, > 36s1u2+36 cas ² 6 + +9 3√5 dt ₂ 36 +9 = (+²+3) ² 355 (2) 45 = (1) flos = < (1²+1) cost, (+²+1) sint, 2√2+> [0, 1] f'(t) = < 2+ cost = (+²+1) sint, 2+sint + (+²+1) cost, 25₂) [[5 "(+1)] = [ (2 + rus+ - (²+1) sint) + (2+ siut + (+²+1) ceat)ª + (252) ² 24th utros't +²+1) 'sin't - Yt last sint (1²+1) + Page No. 4 + ² + ( + ² + 1)² + 3. | 4 + ² + + ² + 2 + ² + 2 + 8 = +² +6+² +9 = 3√5 315 म 2 4+²siv't + (+²+1) ² co²+ + 4 + + ² tusinf lost +8 = T (+²+ ²) 2+ = (+ ² + ²+ ] " + ( + + ³) = 2 Jo TO 3 4 Date <2 cos3t, 2sinst, 2+½> f'(M = < 6 sinst, 6 cosst, 2x² + > f'(t) = <- 6s²u²t, 6coszt 2+¼/2) 11 f'(+))) = ( 6 5²4²4 ) ² + (Gros ²4) ² + . O = fas 0 2 36 sin 34 +26cos ²2+ +9+ 36+9+ 3√√++4 dt = F₂ = J 1 31₂ - 4 ((1+1)^² + 2) = ² | (5) ²2² - ( 1³2 ) 4) 2 0 2 555 - 8) = 1055 -16 f(t) = < 2cus 2t, 2 sinzt, 3+> f'(t) = <- 6sinzt, 6Coszt, 33 Jo 3J++4 ||| f '(x) || = ²8 s³u²2+ + 36 cos ²2+ + 9 = L 3√5 + of Jt tu dt 355 dt first find the fre length function. it L(H = 355+ [0,1] 7 J45 2 355
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
100%
TRANSCRIBE THE FOLLOWING SOLUTION IN DIGITAL FORMAT
![M
Date
<2 cosst, 2sin 3f, 2+³/2>
H
f'(M= < 6sinst
6 cos 3+ 2×3 +²/₂+ >
1
f'(t) = <- 6siu²t,
600s34
8+½/2)
11 f'(+1)] = [(-65²4 ²+)² + (G₁0₂EA)² + (5+2) ²
=
1
36 sin3t +36cos²3+ +9+
36+9+
3√3+4 dt =
और
23 (+4) x 2
F=
3√ ++4
2
O
0
L
315
=
3+>
f(t) = < ?cus 2+ 2 sinzt
f'(t) = <- 6sinzt, (cos2t, 3)
[]18 (+1)]
355 dt
O
2 [ 555 - 8) = 1055 - 16
3sin ²2+ + 36 cos ²2+ +9
Page No.
3/2
2) (5) ²2 - (4) ²/²))
first find the Are length function.
+
L(H) =
2
[0,1]
355+
"Where there is love there is life.T-Mahatma Gandhi
J45
2
355](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45fe7bab-247d-4d9b-8e43-be55c82fe47a%2Fb7a41c88-4c9b-45c2-8410-fe7825d7495f%2F5iz5mjo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:M
Date
<2 cosst, 2sin 3f, 2+³/2>
H
f'(M= < 6sinst
6 cos 3+ 2×3 +²/₂+ >
1
f'(t) = <- 6siu²t,
600s34
8+½/2)
11 f'(+1)] = [(-65²4 ²+)² + (G₁0₂EA)² + (5+2) ²
=
1
36 sin3t +36cos²3+ +9+
36+9+
3√3+4 dt =
और
23 (+4) x 2
F=
3√ ++4
2
O
0
L
315
=
3+>
f(t) = < ?cus 2+ 2 sinzt
f'(t) = <- 6sinzt, (cos2t, 3)
[]18 (+1)]
355 dt
O
2 [ 555 - 8) = 1055 - 16
3sin ²2+ + 36 cos ²2+ +9
Page No.
3/2
2) (5) ²2 - (4) ²/²))
first find the Are length function.
+
L(H) =
2
[0,1]
355+
"Where there is love there is life.T-Mahatma Gandhi
J45
2
355
![Date
(₁) flt1 = < ² cos 24, 2cinzt, 3+2
f'(t)
<bsinzt, 6cos2t, 3>
|| | ' ( ) ) )
Are Length
2 =
0
U
+
Vo
2
36sin²24 +36 (as ² 6 + +9
J45
J36 +9
3√5 dt z
=
355 (1)
Page No.
=
(5) = 3555)
3.15 म
2
(18) flss = < (1²+1) lost, (²+1) sint, 2√2+>
[0, 1]
f'(t) = < 2+ cost = (+²+1) sind, 2+ sint + (+²+1) cost,
252)
115 "(+)|| - | (2 + cus+ - (+²+1) sint) ² + (2+ sixt + (+²+1) Cest) ²
+ (252) ²
=
| 4t²ros²t + (²+1) ² sin't - 4 trustsint (1²+1) +
355
=
4 + ² siv²t + (+²+1) ² (0³²+ + + + ² tusinf lost
+8
4+² + ( + ² + 1)² + 3
4+²+ + ²4 +2+ ² + 2 + 8 = +² + 6 + ³² +9
) (+²+3)² =
(+²+3)
(+²³+²) d+ = (+³² + ²+ ] ' = ( + + 3) −0)
3
0
To
3
Date
Ⓒflt) = <2 cos3t, 2sinst, 2+½/2>
4
O
f'(M = < 6 singt, 6cusst, 2x3 +²₂7 >
t
|f'(t) = <- 6siust,
600334
[11 f' (+))) = [(-65²4 ²+ ) ² + (G₁0₂EA)² + (5+2) ²
1
=
0
3√3+4 dt =
36+ 9+
36sin3t +36 cos²3+ +9+
L(H) =
F₂
2
L
315
2
355 dt
2+1/2)
3J++4
J
3/2
= 12 (4+14)" ² x 2 = 2 | (5) ²2 - (1951)
X
d
+
O
2
Page No.
2 555 - 8) = 1055 - 16/
f(t) = < ?cus 2t, 2 sinzt, 3+>
f(t) = <- 6sinzt, (cos2t, 3)
|| 8² (+) || = 38 sin ²2+ + 36 cos ²2+ + 9 =
first find the Are length function.
fo
0
[0,1]
355+
"Where there is love there is life.T-Mahatira Gandhi
J45 = 315](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45fe7bab-247d-4d9b-8e43-be55c82fe47a%2Fb7a41c88-4c9b-45c2-8410-fe7825d7495f%2Fo58bwnh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Date
(₁) flt1 = < ² cos 24, 2cinzt, 3+2
f'(t)
<bsinzt, 6cos2t, 3>
|| | ' ( ) ) )
Are Length
2 =
0
U
+
Vo
2
36sin²24 +36 (as ² 6 + +9
J45
J36 +9
3√5 dt z
=
355 (1)
Page No.
=
(5) = 3555)
3.15 म
2
(18) flss = < (1²+1) lost, (²+1) sint, 2√2+>
[0, 1]
f'(t) = < 2+ cost = (+²+1) sind, 2+ sint + (+²+1) cost,
252)
115 "(+)|| - | (2 + cus+ - (+²+1) sint) ² + (2+ sixt + (+²+1) Cest) ²
+ (252) ²
=
| 4t²ros²t + (²+1) ² sin't - 4 trustsint (1²+1) +
355
=
4 + ² siv²t + (+²+1) ² (0³²+ + + + ² tusinf lost
+8
4+² + ( + ² + 1)² + 3
4+²+ + ²4 +2+ ² + 2 + 8 = +² + 6 + ³² +9
) (+²+3)² =
(+²+3)
(+²³+²) d+ = (+³² + ²+ ] ' = ( + + 3) −0)
3
0
To
3
Date
Ⓒflt) = <2 cos3t, 2sinst, 2+½/2>
4
O
f'(M = < 6 singt, 6cusst, 2x3 +²₂7 >
t
|f'(t) = <- 6siust,
600334
[11 f' (+))) = [(-65²4 ²+ ) ² + (G₁0₂EA)² + (5+2) ²
1
=
0
3√3+4 dt =
36+ 9+
36sin3t +36 cos²3+ +9+
L(H) =
F₂
2
L
315
2
355 dt
2+1/2)
3J++4
J
3/2
= 12 (4+14)" ² x 2 = 2 | (5) ²2 - (1951)
X
d
+
O
2
Page No.
2 555 - 8) = 1055 - 16/
f(t) = < ?cus 2t, 2 sinzt, 3+>
f(t) = <- 6sinzt, (cos2t, 3)
|| 8² (+) || = 38 sin ²2+ + 36 cos ²2+ + 9 =
first find the Are length function.
fo
0
[0,1]
355+
"Where there is love there is life.T-Mahatira Gandhi
J45 = 315
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 3 images
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
