20000 9750 800 9750 100 1900 1000 Total horizontal load from the blades Total weight force from the blades 1 Distributed wind load on tower = × Pair × wind² × width of the tower Pair = 1.2 kg/ m² Distance from the centre of the blades tothe center of the Tower

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
5th Edition
ISBN:9781305084766
Author:Saeed Moaveni
Publisher:Saeed Moaveni
Chapter4: Engineering Communication
Section: Chapter Questions
Problem 19P
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needing help with bending moment and shear diagram for my wind turbine tower. these are my dimensions. the example free body diagram is provided. The material I am using is S355 steel that has a density of 7850kg/m^3. the tower dimensions are as follows:

  • Width (W) of the column is 1m
  • Depth (D) of the column is 1m
  • Height (H) of the column is 20m
20000
9750
800
9750
100 1900
1000
Transcribed Image Text:20000 9750 800 9750 100 1900 1000
Total horizontal load from the blades
Total weight force from the blades
1
Distributed wind load on tower = × Pair × wind² × width of the tower
Pair = 1.2
kg/
m²
Distance from the centre of the
blades tothe center of the Tower
Transcribed Image Text:Total horizontal load from the blades Total weight force from the blades 1 Distributed wind load on tower = × Pair × wind² × width of the tower Pair = 1.2 kg/ m² Distance from the centre of the blades tothe center of the Tower
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