2000A television camera at ground level is 2000 feet away from the launching pad of a space rocket that isset to take off vertically, as seen in the following figure. The angle of elevation of the camera can befound by 0 = tan-1G2000)where z is the height of the rocket.Find the rate of change of the angle of elevation after launch when the camera and the rocket are4953 feet apart.A' =radians per foot. Round to five decimal places.

Solution:-Given thatθ=tan-1x2000when, camera and rocket are at 4953 feet apart

2000 A television camera at ground level is 2000 feet away from the launching pad of a space rocket that is set to take off vertically, as seen in the following figure. The angle of elevation of the camera can be found by e = tan-1 where a is the height of the rocket. 2000 Find the rate of change of the angle of elevation after launch when the camera and the rocket are 4953 feet apart. O' = radians per foot. Round to five decimal places.

2000 A television camera at ground level is 2000 feet away from the launching pad of a space rocket that is set to take off vertically, as seen in the following figure. The angle of elevation of the camera can be found by e = tan-1 where a is the height of the rocket. 2000 Find the rate of change of the angle of elevation after launch when the camera and the rocket are 4953 feet apart. O' = radians per foot. Round to five decimal places.