20. Roll ten unfair six-sided dice where, for each die, P(one) = 0.08, P(two) = 0.12, P(three) = 0.10, P(four) = 0.22, P(five) = 0.28, P(siz) = 0.20. Find P(1 – 2 -3 - 1 – 2– 1). A. 0.00010086 B. 0.00020086 C. 0.00040086 D. 0.00060086
20. Roll ten unfair six-sided dice where, for each die, P(one) = 0.08, P(two) = 0.12, P(three) = 0.10, P(four) = 0.22, P(five) = 0.28, P(siz) = 0.20. Find P(1 – 2 -3 - 1 – 2– 1). A. 0.00010086 B. 0.00020086 C. 0.00040086 D. 0.00060086
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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can someone please help me solve this :) I really need help thanks so much!!!

Transcribed Image Text:Ticket Machine Setup
Suppose you have a machine that randomly prints out tickets with numbers on them. 17% of the time
the ticket has number 3. 24% of the time the ticket has number 8. 37% of the time the ticket has
number 15. 22% of the time the ticket has number 22. There are no other ticket numbers. Let the
random variable X be the number on the ticket.

Transcribed Image Text:20. Roll ten unfair six-sided dice where, for each die, P(one) = 0.08, P(two) = 0.12, P(three) = 0.10,
P(four) = 0.22, P(five) = 0.28, P(siz) = 0.20. Find P(1 – 2 – 3 – 1 – 2 – 1).
%3D
A. 0.00010086
B. 0.00020086
C. 0.00040086
D. 0.00060086
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