20. (II) A +35 µC point charge is placed 46 cm from an identi- cal +35 µC charge. How much work would be required to move a +0.50 μC test charge from a point midway between them to a point 12 cm closer to either of the charges?

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### Problem Statement

**Question 20:** 

A +35 µC point charge is placed 46 cm from an identical +35 µC charge. How much work would be required to move a +0.50 µC test charge from a point midway between them to a point 12 cm closer to either of the charges?

### Explanation

This is a physics problem involving electrostatics, specifically the calculation of work required to move a test charge in the presence of other point charges. Let's break down the information provided:

1. **Initial Setup:**
   - There are two point charges, each of +35 µC (microcoulombs), placed 46 cm apart.
   - A +0.50 µC test charge is initially placed at the midpoint between these two charges.

2. **Objective:**
   - To calculate the work required to move the +0.50 µC test charge to a point that is 12 cm closer to either of the +35 µC charges.

### Detailed Information:

1. **Initial Distance:**
   - The midpoint between the charges is 23 cm from each +35 µC charge (since 46 cm / 2 = 23 cm).

2. **Final Distance:**
   - After moving the test charge 12 cm closer to one of the charges, the new distance will be (23 cm - 12 cm) = 11 cm from that charge.
   - It will be (23 cm + 12 cm) = 35 cm from the other +35 µC charge.

### Charge Interaction and Formulas:

- The work \( W \) required to move a charge \( q \) in the presence of other charges is given by:
  \[
  W = q \Delta V
  \]
  where \( \Delta V \) is the change in electric potential.

- The electric potential \( V \) at a distance \( r \) from a point charge \( Q \) is:
  \[
  V = \frac{kQ}{r}
  \]
  where \( k \) is Coulomb's constant (\( 8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2 \)).

### Initial and Final Potential:

- **Initial Potential at Midpoint:**
  \[
  V_\text{initial} = \frac{k \cdot 35 \times 10
Transcribed Image Text:### Problem Statement **Question 20:** A +35 µC point charge is placed 46 cm from an identical +35 µC charge. How much work would be required to move a +0.50 µC test charge from a point midway between them to a point 12 cm closer to either of the charges? ### Explanation This is a physics problem involving electrostatics, specifically the calculation of work required to move a test charge in the presence of other point charges. Let's break down the information provided: 1. **Initial Setup:** - There are two point charges, each of +35 µC (microcoulombs), placed 46 cm apart. - A +0.50 µC test charge is initially placed at the midpoint between these two charges. 2. **Objective:** - To calculate the work required to move the +0.50 µC test charge to a point that is 12 cm closer to either of the +35 µC charges. ### Detailed Information: 1. **Initial Distance:** - The midpoint between the charges is 23 cm from each +35 µC charge (since 46 cm / 2 = 23 cm). 2. **Final Distance:** - After moving the test charge 12 cm closer to one of the charges, the new distance will be (23 cm - 12 cm) = 11 cm from that charge. - It will be (23 cm + 12 cm) = 35 cm from the other +35 µC charge. ### Charge Interaction and Formulas: - The work \( W \) required to move a charge \( q \) in the presence of other charges is given by: \[ W = q \Delta V \] where \( \Delta V \) is the change in electric potential. - The electric potential \( V \) at a distance \( r \) from a point charge \( Q \) is: \[ V = \frac{kQ}{r} \] where \( k \) is Coulomb's constant (\( 8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2 \)). ### Initial and Final Potential: - **Initial Potential at Midpoint:** \[ V_\text{initial} = \frac{k \cdot 35 \times 10
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