20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries water to a depth of 40cm and mean velocity of 0.60 m/s. what length of a rectangular contracted weir 85cm high should be placed in the middle of the canal if the depth of water upstream is to be 1.20m? Given:
20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries water to a depth of 40cm and mean velocity of 0.60 m/s. what length of a rectangular contracted weir 85cm high should be placed in the middle of the canal if the depth of water upstream is to be 1.20m? Given:
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Need asap. On the red box, What is that formula ? It is not orifice problem but why there is Ao. Can you put the exact formula? Thank you
![20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries
water to a depth of 40cm and mean velocity of 0.60 m/s. what length of a
rectangular contracted weir 85cm high should be placed in the middle of
the canal if the depth of water upstream is to be 1.20m?
Given:
Find: L =?
H
d=1.20m
P = 0.85
do = 0.40m
H = 1-20-0-85
H = 6.35
original w.s
2,4m
Solution:
L' = 4.28 m
GM
= ½ (6 + 7.6) (0.4) (0.6)
= 1.63m3/s
Q = 1.84 L'H 3/2
1.63 = 1.84 L' (0.35) 3/2
Qo = AoVo
*aam
L = 4.28 +0.20(0.35)
L = 4.35m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F90a775b4-ca1e-495d-9143-56cc1899f56a%2Fba88c434-6bc6-4233-9dc5-146c83f62625%2Fwgax6bh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries
water to a depth of 40cm and mean velocity of 0.60 m/s. what length of a
rectangular contracted weir 85cm high should be placed in the middle of
the canal if the depth of water upstream is to be 1.20m?
Given:
Find: L =?
H
d=1.20m
P = 0.85
do = 0.40m
H = 1-20-0-85
H = 6.35
original w.s
2,4m
Solution:
L' = 4.28 m
GM
= ½ (6 + 7.6) (0.4) (0.6)
= 1.63m3/s
Q = 1.84 L'H 3/2
1.63 = 1.84 L' (0.35) 3/2
Qo = AoVo
*aam
L = 4.28 +0.20(0.35)
L = 4.35m
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