20 x(t)= e 10 nt- u-n)_¸ ¯-¡(10π-÷n) 2j x (1) = -√ [6 / (10 mt - ² m ) _ _ - - ( 10 mt ² x(t) == é -√2/10 m². - 11. j2π 3 -(10m-n)] x(t)== x(t) Fe x(t)=e j10πt-e-j10m. How did he get the value inside the circle? It is possible to explain step by step, a clear line, complete the solution, ¡10nt.e -e-¡10nt.e - fm 6 ㅎ -e-/10mt.e 6
20 x(t)= e 10 nt- u-n)_¸ ¯-¡(10π-÷n) 2j x (1) = -√ [6 / (10 mt - ² m ) _ _ - - ( 10 mt ² x(t) == é -√2/10 m². - 11. j2π 3 -(10m-n)] x(t)== x(t) Fe x(t)=e j10πt-e-j10m. How did he get the value inside the circle? It is possible to explain step by step, a clear line, complete the solution, ¡10nt.e -e-¡10nt.e - fm 6 ㅎ -e-/10mt.e 6
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
i need the answer quickly
![1
1
TIt
-
Tt
-
2 [ 0 (10 - ) - 0 - (10 - )
e
2j
x(t)=2
1
- [6 (10m - 2 x) - (10 m - n)]
T - 0
-
e
₂67]
x(t)=-
x (1) = -√√/10m - fr
x(t)=
T
x(t) Fe
골
j2π
3
e -e-¡10nt.e
π
10π. // T
e
e-¡10nt.e 6
10F)
e
x(t)= e
10πt-e-10m
How did he get the value inside the circle?
It is possible to explain step by step,
a clear line, complete the solution,
and reach the final result
T](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F013331d1-1dfa-497a-847a-05c3002de4bb%2Faff56598-a637-44e7-964c-bdb6bc1c434e%2F4cdzdwl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1
1
TIt
-
Tt
-
2 [ 0 (10 - ) - 0 - (10 - )
e
2j
x(t)=2
1
- [6 (10m - 2 x) - (10 m - n)]
T - 0
-
e
₂67]
x(t)=-
x (1) = -√√/10m - fr
x(t)=
T
x(t) Fe
골
j2π
3
e -e-¡10nt.e
π
10π. // T
e
e-¡10nt.e 6
10F)
e
x(t)= e
10πt-e-10m
How did he get the value inside the circle?
It is possible to explain step by step,
a clear line, complete the solution,
and reach the final result
T
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