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20 V Chc = 6 pF Che = 20 pF Ce = 10 pF Cw, = 7 pF Cw,- = 11 pF %3D 3 kn 470 k2 1 µF 0,6 k2 B = 110 1 µF 4,7 k2 V, 091 ΚΩ 6,8 µF

20 V Chc = 6 pF Che = 20 pF Ce = 10 pF Cw, = 7 pF Cw,- = 11 pF %3D 3 kn 470 k2 1 µF 0,6 k2 B = 110 1 µF 4,7 k2 V, 091 ΚΩ 6,8 µF

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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For the circuit below determine: Zi and Zo

Answer  Zi=747,81Ω

20 V Cw; = 7 pF Cw, = 11 pF Che = 6 pF Che = 20 pF Cee = 10 pF '3 k2 470 k2 1 µF 0,6 kn B = 110 1 µF Z, 4,7 kQ 091 kΩ 6,8 µF
Transcribed Image Text:20 V Cw; = 7 pF Cw, = 11 pF Che = 6 pF Che = 20 pF Cee = 10 pF '3 k2 470 k2 1 µF 0,6 kn B = 110 1 µF Z, 4,7 kQ 091 kΩ 6,8 µF
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