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20 V 50 V 10 mA 8.6 mA 9.4 mA R₁ - 5000 OOA (a) R₁ = 1 k W alıt A B 1 V R₁ - 5000 ww R₂-1 kQ2 Figure 16-1 If the diode is made of silicon in Figure 16-1(b), what is the current? Figure 16-1 ê

20 V 50 V 10 mA 8.6 mA 9.4 mA R₁ - 5000 OOA (a) R₁ = 1 k W alıt A B 1 V R₁ - 5000 ww R₂-1 kQ2 Figure 16-1 If the diode is made of silicon in Figure 16-1(b), what is the current? Figure 16-1 ê

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Analysis of Diode Circuits #### Figure 16-1 Figure 16-1 presents three different diode circuit configurations. 1. **Circuit (a)** - **Supply Voltage (V):** 20V - **Resistor (R1):** 500Ω - **Diode:** Forward-biased (Diode symbol indicates standard orientation) **Explanation:** In this configuration, a 20V supply voltage is applied across a 500Ω resistor and a diode in series. The diode is assumed to be forward-biased. 2. **Circuit (b)** - **Supply Voltage (V):** 1V - **Resistor (R1):** 500Ω - **Diode:** Forward-biased (Same orientation as in (a)) **Explanation:** In this setup, a 1V supply voltage is applied across a 500Ω resistor and a diode in series. The diode remains forward-biased when conducting. 3. **Circuit (c)** - **Supply Voltage (V):** 50V - **Resistor (R1):** 1kΩ - **Resistor (R2):** 1kΩ - **Diode:** Forward-biased (Same orientation as in (a) and (b)) - **Point B:** Common node between diode, \(R1\), and \(R2\) **Explanation:** Here, a 50V supply voltage is applied with two 1kΩ resistors and a diode in series. The resistors are arranged in a T-configuration around the diode, with a common node B. ### Problem Statement The question arises about the current in the silicon diode for Figure 16-1(b), given the options: - 10 mA - 8.6 mA - 9.4 mA - 0 A **To solve this:** Considering the forward voltage drop of a silicon diode typically is about 0.7V, we can determine the current through the circuit in Figure 16-1(b). 1. **Supply Voltage (V):** 1V 2. **Diode's forward voltage (Vf):** 0.7V 3. **Voltage across R1 (Resistor Voltage: \(V_R\)):** \( V - V_f = 1
Transcribed Image Text:### Analysis of Diode Circuits #### Figure 16-1 Figure 16-1 presents three different diode circuit configurations. 1. **Circuit (a)** - **Supply Voltage (V):** 20V - **Resistor (R1):** 500Ω - **Diode:** Forward-biased (Diode symbol indicates standard orientation) **Explanation:** In this configuration, a 20V supply voltage is applied across a 500Ω resistor and a diode in series. The diode is assumed to be forward-biased. 2. **Circuit (b)** - **Supply Voltage (V):** 1V - **Resistor (R1):** 500Ω - **Diode:** Forward-biased (Same orientation as in (a)) **Explanation:** In this setup, a 1V supply voltage is applied across a 500Ω resistor and a diode in series. The diode remains forward-biased when conducting. 3. **Circuit (c)** - **Supply Voltage (V):** 50V - **Resistor (R1):** 1kΩ - **Resistor (R2):** 1kΩ - **Diode:** Forward-biased (Same orientation as in (a) and (b)) - **Point B:** Common node between diode, \(R1\), and \(R2\) **Explanation:** Here, a 50V supply voltage is applied with two 1kΩ resistors and a diode in series. The resistors are arranged in a T-configuration around the diode, with a common node B. ### Problem Statement The question arises about the current in the silicon diode for Figure 16-1(b), given the options: - 10 mA - 8.6 mA - 9.4 mA - 0 A **To solve this:** Considering the forward voltage drop of a silicon diode typically is about 0.7V, we can determine the current through the circuit in Figure 16-1(b). 1. **Supply Voltage (V):** 1V 2. **Diode's forward voltage (Vf):** 0.7V 3. **Voltage across R1 (Resistor Voltage: \(V_R\)):** \( V - V_f = 1
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