20 mA 20mA io (20-10) + 0 Σ5 ΚΩ Vo 2 ΚΩ W Using KVL, KCL, and Ohm law only (Direct Method Only) (Do Not Use any other methods like source Transformations, Superposition, Nodal analysis or Mesh Analysis) 252 (a) Find Vo? +√ (20-15) X5 ks => (b) Find to? -5 (20-10) + 2₁0-5=0 (c) Find the power deliver by the voltage source? P = =>105=740 5 V to = 15mA)

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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20 mA
20mA
io
(20-10)
+
0 Σ5 ΚΩ
Vo
2 ΚΩ
W
Using KVL, KCL, and Ohm law only (Direct Method Only)
(Do Not Use any other methods like source Transformations, Superposition,
Nodal analysis or Mesh Analysis)
252
(a) Find Vo? +√ (20-15) X5 ks =>
(b) Find to? -5 (20-10) + 2₁0-5=0
(c) Find the power deliver by the voltage source?
P =
=>105=740
5 V
to = 15mA)
Transcribed Image Text:20 mA 20mA io (20-10) + 0 Σ5 ΚΩ Vo 2 ΚΩ W Using KVL, KCL, and Ohm law only (Direct Method Only) (Do Not Use any other methods like source Transformations, Superposition, Nodal analysis or Mesh Analysis) 252 (a) Find Vo? +√ (20-15) X5 ks => (b) Find to? -5 (20-10) + 2₁0-5=0 (c) Find the power deliver by the voltage source? P = =>105=740 5 V to = 15mA)
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