20 6 10 Let A = -1 8 5 and let b = B- 1 -2 1 3 W be the set of all linear combinations of the columns of A. a. Is b in W? b. Show that the third column of A is in W? 3 and
20 6 10 Let A = -1 8 5 and let b = B- 1 -2 1 3 W be the set of all linear combinations of the columns of A. a. Is b in W? b. Show that the third column of A is in W? 3 and
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter4: Vector Spaces
Section4.5: Basis And Dimension
Problem 65E: Find a basis for the vector space of all 33 diagonal matrices. What is the dimension of this vector...
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![### Linear Algebra - Vector Spaces
Given the matrix \( A \) and vector \( \mathbf{b} \):
\[ A =
\begin{bmatrix}
2 & 0 & 6 \\
-1 & 8 & 5 \\
1 & -2 & 1
\end{bmatrix}
\]
\[ \mathbf{b} =
\begin{bmatrix}
10 \\
3 \\
3
\end{bmatrix}
\]
Let \( W \) be the set of all linear combinations of the columns of \( A \).
#### Questions to Consider:
**a. Is \(\mathbf{b}\) in \(W\)?**
**b. Show that the third column of \( A \) is in \( W \)?**
#### Explanation:
1. **Vector \( \mathbf{b} \) in \( W \):**
To determine if \(\mathbf{b}\) is in \( W \), we need to solve the equation \( A\mathbf{x} = \mathbf{b} \) for some vector \(\mathbf{x}\). If a solution \(\mathbf{x}\) exists, then \(\mathbf{b}\) is a linear combination of the columns of \( A \), and thus is in \( W \).
2. **Third Column of \( A \) in \( W \):**
The third column of \( A \) can be written as:
\[
\mathbf{a}_3 =
\begin{bmatrix}
6 \\
5 \\
1
\end{bmatrix}
\]
To show that \(\mathbf{a}_3\) is in \( W \), we need to express \(\mathbf{a}_3\) as a linear combination of the columns of \( A \). This means finding scalars \( c_1 \), \( c_2 \), and \( c_3 \) such that:
\[
c_1 \mathbf{a}_1 + c_2 \mathbf{a}_2 + c_3 \mathbf{a}_3 = \mathbf{a}_3
\]
where \( \mathbf{a}_1 \), \( \mathbf{a}_2 \), and \( \mathbf{a}_3 \) are the first, second, and third columns of](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5ecf1484-f95f-4119-9858-43c8382b92c0%2Ff7ab857b-4e42-41f4-b540-afdc238793bc%2Frqibew_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Linear Algebra - Vector Spaces
Given the matrix \( A \) and vector \( \mathbf{b} \):
\[ A =
\begin{bmatrix}
2 & 0 & 6 \\
-1 & 8 & 5 \\
1 & -2 & 1
\end{bmatrix}
\]
\[ \mathbf{b} =
\begin{bmatrix}
10 \\
3 \\
3
\end{bmatrix}
\]
Let \( W \) be the set of all linear combinations of the columns of \( A \).
#### Questions to Consider:
**a. Is \(\mathbf{b}\) in \(W\)?**
**b. Show that the third column of \( A \) is in \( W \)?**
#### Explanation:
1. **Vector \( \mathbf{b} \) in \( W \):**
To determine if \(\mathbf{b}\) is in \( W \), we need to solve the equation \( A\mathbf{x} = \mathbf{b} \) for some vector \(\mathbf{x}\). If a solution \(\mathbf{x}\) exists, then \(\mathbf{b}\) is a linear combination of the columns of \( A \), and thus is in \( W \).
2. **Third Column of \( A \) in \( W \):**
The third column of \( A \) can be written as:
\[
\mathbf{a}_3 =
\begin{bmatrix}
6 \\
5 \\
1
\end{bmatrix}
\]
To show that \(\mathbf{a}_3\) is in \( W \), we need to express \(\mathbf{a}_3\) as a linear combination of the columns of \( A \). This means finding scalars \( c_1 \), \( c_2 \), and \( c_3 \) such that:
\[
c_1 \mathbf{a}_1 + c_2 \mathbf{a}_2 + c_3 \mathbf{a}_3 = \mathbf{a}_3
\]
where \( \mathbf{a}_1 \), \( \mathbf{a}_2 \), and \( \mathbf{a}_3 \) are the first, second, and third columns of
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