20 (4.) Calculate (F. dr, where F = (y² + z², x² + z², x² + y²) and C is the boundary of the triangle cut C from the plane 2x+y+z = 1 by the first octant, travelled counterclockwise when viewed from above. Stoker: Fier SSAXE.ds (190) (0,1,0) y=2x+1 -594 = z=1-2x-4 <2,1,1> ی DXF dx dy x²+Z² = <24-27, 22-2x, 2x-24> Region in хурвые =) =) √x F¬ds = [2 [2y-22] + 2Z-2x + 2x-2y] dA SSSS (44 +4x-2) dy dx 2 2 • (22 +419-23)112 +4ху-24 0 = Σ (1-2x) + 2x (1-2x) - (1-2x)) = (45-47+27 9(25-22)da = -xx-x√2x-2y) dd on surface (2y-2 [1-2x-9]) d (24 -2+4x+2y)dA (4y+4x-2)dA ½ 1-2× SS (44+4x-2)dy dx 00 dx -*x +4/2² + xx-/4x² +1 + xx] dt ' (od x
20 (4.) Calculate (F. dr, where F = (y² + z², x² + z², x² + y²) and C is the boundary of the triangle cut C from the plane 2x+y+z = 1 by the first octant, travelled counterclockwise when viewed from above. Stoker: Fier SSAXE.ds (190) (0,1,0) y=2x+1 -594 = z=1-2x-4 <2,1,1> ی DXF dx dy x²+Z² = <24-27, 22-2x, 2x-24> Region in хурвые =) =) √x F¬ds = [2 [2y-22] + 2Z-2x + 2x-2y] dA SSSS (44 +4x-2) dy dx 2 2 • (22 +419-23)112 +4ху-24 0 = Σ (1-2x) + 2x (1-2x) - (1-2x)) = (45-47+27 9(25-22)da = -xx-x√2x-2y) dd on surface (2y-2 [1-2x-9]) d (24 -2+4x+2y)dA (4y+4x-2)dA ½ 1-2× SS (44+4x-2)dy dx 00 dx -*x +4/2² + xx-/4x² +1 + xx] dt ' (od x
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please review and solve the following problem. The screenshot listed already has some work done and the correct answer listed. Please solve the problem and include an explanation of how the work was solved. Also, Please make sure to double check the answer provided matches up with the screenshot and the work is properly formatted so I am able to follow along. Thanks :)
![20
(4.) Calculate (F. dr, where F
=
(y² + z², x² + z², x² + y²) and C is the boundary of the triangle cut
C
from the plane 2x+y+z = 1 by the first octant, travelled counterclockwise when viewed from above.
Stoker: Fier SSAXE.ds
(190)
(0,1,0)
y=2x+1
-594
=
z=1-2x-4
<2,1,1>
ی
DXF
dx
dy
x²+Z²
=
<24-27, 22-2x, 2x-24>
Region in
хурвые
=)
=)
√x F¬ds = [2 [2y-22] + 2Z-2x + 2x-2y] dA
SSSS (44 +4x-2) dy dx
2
2
• (22 +419-23)112
+4ху-24
0
=
Σ (1-2x) + 2x (1-2x) - (1-2x))
=
(45-47+27
9(25-22)da
=
-xx-x√2x-2y) dd
on surface
(2y-2 [1-2x-9]) d
(24
-2+4x+2y)dA
(4y+4x-2)dA
½ 1-2×
SS (44+4x-2)dy dx
00
dx
-*x +4/2² + xx-/4x² +1 + xx] dt
' (od x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4effdf1a-67d0-42fb-b95c-7c4b54ad0624%2F6a1e8bd0-61c8-4131-9dc2-994772555c2f%2F6upmyw_processed.png&w=3840&q=75)
Transcribed Image Text:20
(4.) Calculate (F. dr, where F
=
(y² + z², x² + z², x² + y²) and C is the boundary of the triangle cut
C
from the plane 2x+y+z = 1 by the first octant, travelled counterclockwise when viewed from above.
Stoker: Fier SSAXE.ds
(190)
(0,1,0)
y=2x+1
-594
=
z=1-2x-4
<2,1,1>
ی
DXF
dx
dy
x²+Z²
=
<24-27, 22-2x, 2x-24>
Region in
хурвые
=)
=)
√x F¬ds = [2 [2y-22] + 2Z-2x + 2x-2y] dA
SSSS (44 +4x-2) dy dx
2
2
• (22 +419-23)112
+4ху-24
0
=
Σ (1-2x) + 2x (1-2x) - (1-2x))
=
(45-47+27
9(25-22)da
=
-xx-x√2x-2y) dd
on surface
(2y-2 [1-2x-9]) d
(24
-2+4x+2y)dA
(4y+4x-2)dA
½ 1-2×
SS (44+4x-2)dy dx
00
dx
-*x +4/2² + xx-/4x² +1 + xx] dt
' (od x
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