Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
100%

Transcribed Image Text:The image depicts a number line ranging from -20 to 20. Two points, marked as E and F, are highlighted on this number line. Point E is located at -5, and point F is located at 10.
Beneath the number line, the question is posed: "What is the length of line segment EF?"
### Explanation:
To find the length of the line segment EF, calculate the distance between the two points on the number line.
- **Position of E**: -5
- **Position of F**: 10
**Length of EF** = |10 - (-5)| = |10 + 5| = 15
Therefore, the length of line segment EF is 15 units.
Expert Solution

Introduction:
This is the simple problem based on number system where we find the distance between two points as:
As we know the length of any line segment is equal to the distance between the two extreme points.
Step by step
Solved in 2 steps
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