-20 = -0-14 ue lo 1 14 20 %3D tan-5 - 2 tan'5c =-707 =-132" %3D Phase Margin (PM) = 180 + LGoslouge : 180 -132 PM:481 -tanlol-2tant ol - 665 %3D - tan, -2 tan- - -56.92 1. Lacw>lw-10 -174.6 %3D Laca) lw-5 = - 246-3'
-20 = -0-14 ue lo 1 14 20 %3D tan-5 - 2 tan'5c =-707 =-132" %3D Phase Margin (PM) = 180 + LGoslouge : 180 -132 PM:481 -tanlol-2tant ol - 665 %3D - tan, -2 tan- - -56.92 1. Lacw>lw-10 -174.6 %3D Laca) lw-5 = - 246-3'
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Explain the math logic SIMPLY!
![-20 =
14
A Wsc = 5 rads
%3D
- tan-5 -2tan'5c =-787=-132"
%3D
Phase Margin (PM) = l80 + LGocso low
: 180-132
PM:481
- tan ol-2 tan ol
- - 6:05'
/0
D.1
- tant, -2 tan
- -56.92
1.
-174.6
%3D
Laca) lwiso =
- 246-3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc78e66a6-0428-4a28-bf85-72fa25c7e828%2F0b62bbe1-3306-45d6-a5c7-0fc580acba3d%2F1n3v67_processed.jpeg&w=3840&q=75)
Transcribed Image Text:-20 =
14
A Wsc = 5 rads
%3D
- tan-5 -2tan'5c =-787=-132"
%3D
Phase Margin (PM) = l80 + LGocso low
: 180-132
PM:481
- tan ol-2 tan ol
- - 6:05'
/0
D.1
- tant, -2 tan
- -56.92
1.
-174.6
%3D
Laca) lwiso =
- 246-3
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