(2.x + y)dx + (x – 2y)dy = 0

Q: Differentiate the function. y = V 3x2 + 8x + 1 dy dx

A:

Q: dy + 3x?y = x', x?, y(0) = 2. %3D dx

A: The given differential equation is  dy/dx + 3x2y = x2 y(0) = 2

Q: H.w: find dy dx 1- y=-10x+3cosx

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Q: Find dy dx xy + y² = 5 dy-0

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Q: (2x + ) dx + ( – 2y) dy = 0 12. (2х + 1+x?y², 1+x²y²

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Q: dy Find for y= x(7x+9) dx dy dx

A: We use product rule

Q: (y²-xy )dx + x² dy te

A: Given that, (y2 - xy)dx + x2dy = 0 We have to find the general solution of the given differential…

Q: dy y = (3x2 + x-2)-1; dx

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Q: (x + y²)x dx + (x² + y)y dy = 0

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Q: dy +y de : 2 et dx Arowar 1- ye" (c -x*) 1= yet (c -x*) %3D

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Q: xdy/dx + xy + y − x3 = 0

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Q: y³ + x = x³ + xy. What are the values of dy/dx where y = 0.

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Q: dy_ sec²y 1- 1+x² 2 when x=0 O y=

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Q: (2y? + 2y + 4x²)dx +(2xy +x)dy = 0; when x =- 1 and y = 0 %3D

A: Let's find.

Q: (x + 2y)dx + x dy = 0.

A: Differential equation.

Q: y = (3 – 4x)+/²(7 – 5x²)+/a dy dx

A: This can be solved as follows:

Q: y= In]3x+2)²/2x–1 dy 1. Find dx

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Q: (2x y) dx = -x dy

A:

Q: d?y 1- xy = x + y dx2

A: Given that: 1-xy=x+y

Q: (x²-3y2) dx + 2xy dy =o

A: To solve the following differential equation.x2-3y2 dx+2xy dy=0

Q: Evaluate (2x – y) dx + (x + 6y) dy. C: x-axis from x = 0 to x = 3

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Q: dy + (1x dx 7)y = 2x°

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Q: /3x y dy dx 12.

A: Let I=∫02∫x3xydydx Solve above integral.

Q: Y(Gyt-x-4)dx + 2x dy =0

A: let

Q: тр (няжет хр туть бу

A:

Q: 3. ( 2x-y+ 2) dy + (x- 2y+4) dx =0

A:

Q: (x+y+2) dy dx dz

A: The given integral is: ∫-11∫-11∫-11x+y+zdydxdz