So this is regarding linear Models. Recently got my homework back and noticed the professor marked my answer wrong. This question in particular is about finding the Penrose inverse a matrix A. The only feedback my professor gave me was that the matrix S should be defined as S=A'A, not S=AA'. In this case, what would the correct answer be, and why? 2. IS TA'AA' = A', then K=TA' is the Penrose inverse of A. (this principle to find the Penrose inverse of:011A=1011110→122• A² = ( ² ! ! ) ; S = A + A² (41)(99)-(6)•tece (S) = 6; dr (5)=2xhi (12)-2. der (12) + 1=det (22) = 0(2²) + ((24) + ((32) = 0+3+3=6●cheederistic edynovial= 1³²-61² +6X =05³-65² +65=0obS&s1.€ (61-5) ²165=65²-5³S = 6• T-S*S=A•T* A² × A ×A¹ ×A` -- I× A² × A• K=TxA¹ i Pen_iny. of A· K=TXA¹ → ☎ [613](H)1 (33-3) (193)4-2-1=-24-1K= (3²3)Xतत6 [390]- (23/12)-001[888)-(3ततल

Given Data: Let us consider the given matrix is A=011011110 If TA'AA'=A', then K=TA' is the Penrose…

2.IS TA'AA'=A', then K=TA' is the Penrose inverse of A. Use this principle to find the Rearase inverse of: (011) A=1012 • A² - (!); S>A»A` -4999)-(AT) 21 • trece (S) = 6· did (5) = 2xchi (1:2)-2^ det (22) + 1^ det (22) = 0 011 21 b=^²)+(34) + (32) = 0+3+3=6 -cheederistic plymanals 1²³-61² +6X = 0 5³-65² +65 =0 65=65²-5³ 2 2 2 5= 3(61-5) 5² SAS J

2.IS TA'AA'=A', then K=TA' is the Penrose inverse of A. Use this principle to find the Rearase inverse of: (011) A=1012 • A² - (!); S>A»A` -4999)-(AT) 21 • trece (S) = 6· did (5) = 2xchi (1:2)-2^ det (22) + 1^ det (22) = 0 011 21 b=^²)+(34) + (32) = 0+3+3=6 -cheederistic plymanals 1²³-61² +6X = 0 5³-65² +65 =0 65=65²-5³ 2 2 2 5= 3(61-5) 5² SAS J

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

So this is regarding linear Models. Recently got my homework back and noticed the professor marked my answer wrong. This question in particular is about finding the Penrose inverse a matrix A. The only feedback my professor gave me was that the matrix S should be defined as S=A'A, not S=AA'. In this case, what would the correct answer be, and why?

2. IS TA'AA' = A', then K=TA' is the Penrose inverse of A. (
this principle to find the Penrose inverse of:
011
A=1011
110
→
122
• A² = ( ² ! ! ) ; S = A + A² (41)(99)-(6)
•tece (S) = 6; dr (5)=2xhi (12)-2. der (12) + 1=det (22) = 0
(2²) + ((24) + ((32) = 0+3+3=6
●cheederistic edynovial= 1³²-61² +6X =0
5³-65² +65=0
ob
S&s
1.
€ (61-5) ²1
65=65²-5³
S = 6
• T-S*S=A
•T* A² × A ×A¹ ×A` -- I× A² × A
• K=TxA¹ i Pen_iny. of A
· K=TXA¹ → ☎ [613](H)
1 (33-3) (193)
4-2-1
=
-24-1
K= (3²3)
X
तत
6 [390]- (23/12)
-001
[888)-(3
ततल

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