2.82 g of canola oil were titrated with KOH. It required 16.09 mL of 0.0040 M KOH to reach the equivalence point. What is the acid number? Your Answer: Answer units

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 42QAP: A solution of KOH has a pH of 13.29. It requires 27.66 mL of 0.2500 M HCI to reach the equivalence...
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2.82 g of canola oil were titrated with KOH. It required 16.09 mL of 0.0040 M KOH to reach the equivalence point. What is the acid number?

2.82 g of canola oil were titrated with KOH. It required 16.09 mL of 0.0040 M KOH
to reach the equivalence point. What is the acid number?
Your Answer:
Answer
units
Transcribed Image Text:2.82 g of canola oil were titrated with KOH. It required 16.09 mL of 0.0040 M KOH to reach the equivalence point. What is the acid number? Your Answer: Answer units
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