2.7 Position Vectors Learning Goal: To find a position vector between two arbitrary points. As shown, two cables connect three points. C is below A by a distance C₂ = 1.50 ft and connected to A by a cable 12.1 ft long. Cable AC forms an angle = 17.0° with the positive y axis. B is 7.90 ft above C and the distances B₂ and By are 7.10 ft and 4.70 ft, respectively. (Figure 1 > Figure B Part A Position vector from A to B TAB= < 1 of 1 JC₂ c. Using the dimensions in the figure, find the position vector from A to B in component form. Express your answers, separated by commas, to three significant figures. ▸ View Available Hint(s) 197| ΑΣΦ | 11 | vec ↑ → og ? ift, jft, k ft Part B - Unit direction vector for line AB For the position vector found in Part A, find the unit direction vector acting in the same direction. Express your answer in component form. Express your answers, separated by commas, to three significant figures. ▸ View Available Hint(s) UAB= 197| ΑΣΦ | 11 | vec Part C Position vector from A to C . TAC == 3 195] ΑΣΦ. 11, vec → C gag ? The length of cable AC is 12.1 ft, and the cable forms the angle B 17.0° with the y axis. Given this information and the dimensions provided in the figure, find the position vector from A to C. Express the position vector in component form. Express your answers, separated by commas, to three significant figures. ▸ View Available Hint(s) n → i, j, k ? ift, jft, k ft C
2.7 Position Vectors Learning Goal: To find a position vector between two arbitrary points. As shown, two cables connect three points. C is below A by a distance C₂ = 1.50 ft and connected to A by a cable 12.1 ft long. Cable AC forms an angle = 17.0° with the positive y axis. B is 7.90 ft above C and the distances B₂ and By are 7.10 ft and 4.70 ft, respectively. (Figure 1 > Figure B Part A Position vector from A to B TAB= < 1 of 1 JC₂ c. Using the dimensions in the figure, find the position vector from A to B in component form. Express your answers, separated by commas, to three significant figures. ▸ View Available Hint(s) 197| ΑΣΦ | 11 | vec ↑ → og ? ift, jft, k ft Part B - Unit direction vector for line AB For the position vector found in Part A, find the unit direction vector acting in the same direction. Express your answer in component form. Express your answers, separated by commas, to three significant figures. ▸ View Available Hint(s) UAB= 197| ΑΣΦ | 11 | vec Part C Position vector from A to C . TAC == 3 195] ΑΣΦ. 11, vec → C gag ? The length of cable AC is 12.1 ft, and the cable forms the angle B 17.0° with the y axis. Given this information and the dimensions provided in the figure, find the position vector from A to C. Express the position vector in component form. Express your answers, separated by commas, to three significant figures. ▸ View Available Hint(s) n → i, j, k ? ift, jft, k ft C
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![2.7 Position Vectors
Learning Goal:
To find a position vector between two arbitrary
points.
As shown, two cables connect three points. C is
below A by a distance C₂ = 1.50 ft and
connected to A by a cable 12.1 ft long. Cable AC
forms an angle B = 17.0° with the positive y axis.
B is 7.90 ft above C and the distances B₂ and
By are 7.10 ft and 4.70 ft, respectively. (Figure 1
>
Figure
B
с
Part A - Position vector from A to B
TAB=
C₂
Cx
Using the dimensions in the figure, find the position vector from A to B in component form.
Express your answers, separated by commas, to three significant figures.
► View Available Hint(s)
1 of 1
15|
Ψ—| ΑΣΦ11 | vec 3
?
ift, j ft, k ft
Part B - Unit direction vector for line AB
For the position vector found in Part A, find the unit direction vector acting in the same direction. Express your
answer in component form.
Express your answers, separated by commas, to three significant figures.
► View Available Hint(s)
UAB =
15. ΑΣΦ
V
Part C - Position vector from A to C
TAC =
↓↑
15] ΑΣΦ
vec 6
➜
↓↑ vec
P
The length of cable AC is 12.1 ft, and the cable forms the angle B = 17.0° with the y axis. Given this
information and the dimensions provided in the figure, find the position vector from A to C. Express the position
vector in component form.
Express your answers, separated by commas, to three significant figures.
►View Available Hint(s)
?
?
i, j, k
ift, j ft, k ft](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4b096e23-0624-436f-a8d4-1120c037fff2%2F3c9e6c37-aa89-43e1-946f-3f2f9012ae15%2Fe64v9v_processed.png&w=3840&q=75)
Transcribed Image Text:2.7 Position Vectors
Learning Goal:
To find a position vector between two arbitrary
points.
As shown, two cables connect three points. C is
below A by a distance C₂ = 1.50 ft and
connected to A by a cable 12.1 ft long. Cable AC
forms an angle B = 17.0° with the positive y axis.
B is 7.90 ft above C and the distances B₂ and
By are 7.10 ft and 4.70 ft, respectively. (Figure 1
>
Figure
B
с
Part A - Position vector from A to B
TAB=
C₂
Cx
Using the dimensions in the figure, find the position vector from A to B in component form.
Express your answers, separated by commas, to three significant figures.
► View Available Hint(s)
1 of 1
15|
Ψ—| ΑΣΦ11 | vec 3
?
ift, j ft, k ft
Part B - Unit direction vector for line AB
For the position vector found in Part A, find the unit direction vector acting in the same direction. Express your
answer in component form.
Express your answers, separated by commas, to three significant figures.
► View Available Hint(s)
UAB =
15. ΑΣΦ
V
Part C - Position vector from A to C
TAC =
↓↑
15] ΑΣΦ
vec 6
➜
↓↑ vec
P
The length of cable AC is 12.1 ft, and the cable forms the angle B = 17.0° with the y axis. Given this
information and the dimensions provided in the figure, find the position vector from A to C. Express the position
vector in component form.
Express your answers, separated by commas, to three significant figures.
►View Available Hint(s)
?
?
i, j, k
ift, j ft, k ft
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