2.5 We want to use left-hand, right-hand, and midpoint approximations with n = 4 subintervals of equal width to estimate 1.25z dx. -0.5 (a) The width of each subinterval is Ax = (b) If we use a left-hand approximation, then the left-hand endpoints are (as a comma-separated list). The left-hand approximation is L4 = ( (c) If we use a right-hand approximation, then the right-hand endpoints are (as a comma-separated list). The right-hand approximation is R4 = ( (d) If we use a midpoint approximation, then the midpoints are (as a comma-separated list). The midpoint approximation is M4 = +

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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2.5
We want to use left-hand, right-hand, and midpoint approximations with n = 4 subintervals of equal width to estimate
e1.25x dr.
-0.5
(a) The width of each subinterval is Ax =
(b) If we use a left-hand approximation, then the left-hand endpoints are
(as a comma-separated list).
The left-hand approximation is
L4 = (
+
(c) If we use a right-hand approximation, then the right-hand endpoints are
(as a comma-separated list).
The right-hand approximation is
R4 =
(d) If we use a midpoint approximation, then the midpoints are
(as a comma-separated list).
The midpoint approximation is
M4 =
+
Transcribed Image Text:2.5 We want to use left-hand, right-hand, and midpoint approximations with n = 4 subintervals of equal width to estimate e1.25x dr. -0.5 (a) The width of each subinterval is Ax = (b) If we use a left-hand approximation, then the left-hand endpoints are (as a comma-separated list). The left-hand approximation is L4 = ( + (c) If we use a right-hand approximation, then the right-hand endpoints are (as a comma-separated list). The right-hand approximation is R4 = (d) If we use a midpoint approximation, then the midpoints are (as a comma-separated list). The midpoint approximation is M4 = +
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