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2.4. Find the half-power beamwidth (HPBW) and first-null beamwidth (FNBW), in radians and degrees, for the following normalized radiation intensities: (b) U(0) = cos² 0 (a) U(0) = cos 0 (c) U(0) = cos(20) (d) U(0) = cos²(20)}(0 < 0 < 90°,0 < ¢ < 360°) (e) U(0) = cos(360) (f) U(0) = cos²(30)

2.4. Find the half-power beamwidth (HPBW) and first-null beamwidth (FNBW), in radians and degrees, for the following normalized radiation intensities: (b) U(0) = cos² 0 (a) U(0) = cos 0 (c) U(0) = cos(20) (d) U(0) = cos²(20)}(0 < 0 < 90°,0 < ¢ < 360°) (e) U(0) = cos(360) (f) U(0) = cos²(30)

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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2.4. Find the half-power beamwidth (HPBW) and first-null beamwidth (FNBW), in radians and degrees, for the following normalized radiation intensities: (a) U(0) = cos 0 (b) U(0) = cos? e (c) U(0) = cos(20) (d) U(0) = cos²(20)}(0< 0 < 90°, 0 < ¢ < 360°) (e) U(0) = cos(360) (f) U(0) = cos²(30)
Transcribed Image Text:2.4. Find the half-power beamwidth (HPBW) and first-null beamwidth (FNBW), in radians and degrees, for the following normalized radiation intensities: (a) U(0) = cos 0 (b) U(0) = cos? e (c) U(0) = cos(20) (d) U(0) = cos²(20)}(0< 0 < 90°, 0 < ¢ < 360°) (e) U(0) = cos(360) (f) U(0) = cos²(30)
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