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[2.4] The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average, it consumed 10 W of static power and 90 W of dynamic power. The Core i5 Ivy Bridge, released in 2012, has a clock rate of 3.4 GHz and voltage of 0.9 V. Assume that, on average, it consumed 30 W of static power and 40 W of dynamic power. a. For each processor find the average capacitive loads. Ans. Pentium 4: C = 3.2x10 Farad(F) Core i5: C= 2.9x108 F b. Find the percentage of the total dissipated power comprised by static power and the ratio of static power to dynamic power for each technology. Ans. Pentium 4: 10%- Core i5: 42.9% age be c. If the total dissipated power is to be reduced by 10%, how much should the reduced to maintain the same leakage current? Note: power is defined as the product of voltage and current. Ans. Pentium 4: Vnew = 1.18 Volt(V) Core i5: Vnew = 0.84 V

[2.4] The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average, it consumed 10 W of static power and 90 W of dynamic power. The Core i5 Ivy Bridge, released in 2012, has a clock rate of 3.4 GHz and voltage of 0.9 V. Assume that, on average, it consumed 30 W of static power and 40 W of dynamic power. a. For each processor find the average capacitive loads. Ans. Pentium 4: C = 3.2x10 Farad(F) Core i5: C= 2.9x108 F b. Find the percentage of the total dissipated power comprised by static power and the ratio of static power to dynamic power for each technology. Ans. Pentium 4: 10%- Core i5: 42.9% age be c. If the total dissipated power is to be reduced by 10%, how much should the reduced to maintain the same leakage current? Note: power is defined as the product of voltage and current. Ans. Pentium 4: Vnew = 1.18 Volt(V) Core i5: Vnew = 0.84 V

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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[2.4] The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average, it consumed 10 W of static power and 90 W of dynamic power. The Core i5 Ivy Bridge, released in 2012, has a clock rate of 3.4 GHz and voltage of 0.9 V. Assume that, on average, it consumed 30 W of static power and 40 W of dynamic power. a. For each processor find the average capacitive loads. Ans. Pentium 4: C = 3.2×10 Farad(F) Core i5: C= 2.9x10 F b. Find the percentage of the total dissipated power comprised by static power and the ratio of static power to dynamic power for each technology. Ans. Pentium 4: 10%- Core i5: 42.9% c. If the total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current? Note: power is defined as the product of voltage and current. Ans. Pentium 4: Vnew = 1.18 Volt(V) Core i5: Vnew = 0.84 V
Transcribed Image Text:[2.4] The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average, it consumed 10 W of static power and 90 W of dynamic power. The Core i5 Ivy Bridge, released in 2012, has a clock rate of 3.4 GHz and voltage of 0.9 V. Assume that, on average, it consumed 30 W of static power and 40 W of dynamic power. a. For each processor find the average capacitive loads. Ans. Pentium 4: C = 3.2×10 Farad(F) Core i5: C= 2.9x10 F b. Find the percentage of the total dissipated power comprised by static power and the ratio of static power to dynamic power for each technology. Ans. Pentium 4: 10%- Core i5: 42.9% c. If the total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current? Note: power is defined as the product of voltage and current. Ans. Pentium 4: Vnew = 1.18 Volt(V) Core i5: Vnew = 0.84 V
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