2.37 A U-tube manometer is connected to a closed tank contain-ing air and water as shown in Fig. P2.37. At the closed end of themanometer the air pressure is 16 psia. Determine the reading on thepressure gage for a differential reading of 4 ft on the manometer.Express your answer in psi (gage). Assume standard atmosphericpressure and neglect the weight of the air columns in the manometer.Closed valve-Air pressure = 16 psia4 ftGage fluid(y=90 lb/ft³)Figure P2.37AirWaterT2 ftPressuregage

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Description: 2.37 A U-tube manometer is connected to a closed tank contain-ing air and water as shown in Fig. P2.37. At the closed end of themanometer the air pressure is 16 psia. Determine the reading on thepressure gage for a differential reading of 4 ft on th

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2.37 A U-tube manometer is connected to a closed tank con ing air and water as shown in Fig. P2.37. At the closed end of manometer the air pressure is 16 psia. Determine the reading or pressure gage for a differential reading of 4 ft on the manom Express your answer in psi (gage). Assume standard atmosph pressure and neglect the weight of the air columns in the manom F Closed valve

2.37 A U-tube manometer is connected to a closed tank con ing air and water as shown in Fig. P2.37. At the closed end of manometer the air pressure is 16 psia. Determine the reading or pressure gage for a differential reading of 4 ft on the manom Express your answer in psi (gage). Assume standard atmosph pressure and neglect the weight of the air columns in the manom F Closed valve

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question 2 pls. Complete solution and unit
the system in the figure is in equilibrium. Calculate the gauge pressure (Pg= … kPa) measured on the manometer at the bottom and the height of the mercury in the column (ZHg= …m)? You choose the density and gravity value of mercury, water. The value of the mass on the piston will be M=229kg.
Q2 (a) The system that is shown in Figure Q2 (a) is used to measure the pressure changes AP in the water pipe. When Ah = 7 mm, what is the change in the pipe pressure?
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The system in the figure is in equilibrium. Calculate the gauge pressure (Pg= … kPa) measured on the manometer at the bottom and the height of the mercury in the column (ZHg= …m)? You choose the density and gravity value of mercury, water. The value of the mass on the piston will be M=229kg.
Q22
With the manometer reading as shown in Fig. 2.33, calculate the difference of pressures in the two tubes A and B containing water. [Ans. 9.07 kPa] 1.65 m 80.25 m T 0.5,m & -Oil sp. gr. 0.9 Water-- Fig. 2.33. B
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1. Two pipes A & B caries an oil of specific gravities 0.9 & 1.2 respectively. The center of the pipe A is 75 cm above the pipe B. The height of oil in right limb is 35 cm. Also, the mercury level difference is found in right limb as 60 cm. Find the pressure difference between these two pipes in kPa. Also find the pressure equivalent in water head in mm. A. The difference of pressure between two pipes (PA-Pa) (Unit is in kPa) = B. Equivalent to Water head in mm =
3.4 The tank shown in the figure is filled with a liquid and completely closed to be pressurized under a pressure Pair Determine the gage air pressure above the liquid A in bars. Take: l = 3.65 m, 12 = 1.25 m, 13 = 1.25 m, h = 1.15 m, hɔ = 0.85 m, Sg-A = 1.2, Sg-B = 1.0, Sg-c = 0.85, SHe = 13.6. Patm Reservoir, A Pair Liquid A 12 Mercury 3/4