2.3 Sig Fig Practice 5 Name Julan Eigoth Date 2.3 Sig Figs & Rounding A. Indicate the number of significant figures then round each to the number of significant figures indicated. Еxample: 1.234 cm has 4 significant figures and, rounded to 2 significant figures, is 1.2 1. 0.6034 m significant figures and, rounded to significant figures, is O.GO has 2. 12,700 g has significant figures and, rounded to significant figures, is 3. 12,700.00 g has significant figures and, rounded to 1 significant figures, is 4. 0.000983 m has significant figures and, rounded to 2 significant figures, is 123342.9 g has y significant figures and, rounded to significant figures, is 5. 6. 6.023 x 1023 g has significant figures and, rounded to 2 significant figures, is 7. .005600 m has 2 significant figures and, rounded to 1 significant figures, is 8. 10000.5006 g has a significant figures and, rounded to 5 significant figures, is 9. 2.0 x 10*m has significant figures and, rounded to significant figures, is 10. 3.456110 s has significant figures and, rounded to 3 significant figures, is M/ M/M
2.3 Sig Fig Practice 5 Name Julan Eigoth Date 2.3 Sig Figs & Rounding A. Indicate the number of significant figures then round each to the number of significant figures indicated. Еxample: 1.234 cm has 4 significant figures and, rounded to 2 significant figures, is 1.2 1. 0.6034 m significant figures and, rounded to significant figures, is O.GO has 2. 12,700 g has significant figures and, rounded to significant figures, is 3. 12,700.00 g has significant figures and, rounded to 1 significant figures, is 4. 0.000983 m has significant figures and, rounded to 2 significant figures, is 123342.9 g has y significant figures and, rounded to significant figures, is 5. 6. 6.023 x 1023 g has significant figures and, rounded to 2 significant figures, is 7. .005600 m has 2 significant figures and, rounded to 1 significant figures, is 8. 10000.5006 g has a significant figures and, rounded to 5 significant figures, is 9. 2.0 x 10*m has significant figures and, rounded to significant figures, is 10. 3.456110 s has significant figures and, rounded to 3 significant figures, is M/ M/M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question

Transcribed Image Text:2.3 Sig Fig Practice 5
Name Julan Eigoth
Date
2.3 Sig Figs & Rounding
A. Indicate the number of significant figures then round each to the number of significant figures indicated.
Eхample:
1.234 cm
has
4
significant figures and, rounded to 2
significant figures, is
1.2
1.
0.6034 m
has
significant figures and, rounded to
significant figures, is O.GO
2.
12,700 g
has
significant figures and, rounded to
significant figures, is
3.
12,700.00 g has
significant figures and, rounded to
1
significant figures, is
4.
0.000983 m has
significant figures and, rounded to
significant figures, is
5.
123342.9 g has
Z significant figures and, rounded to
significant figures, is
5
6.
6.023 x 1023 g has
significant figures and, rounded to 2
significant figures, is
7.
.005600 m has
2.
significant figures and, rounded to
1
significant figures, is
8.
10000.5006 g has
5L significant figures and, rounded to 5
significant figures, is
2.0 x 10³m has
significant figures and, rounded to
significant figures, is
9.
1
10.
3.456110 s has
significant figures and, rounded to
3
significant figures, is
B. Given calculations with the calculator answer, write the answers with the appropriate number of significant figures
AND CORRECT UNITS.
Example:
6.00 m x 3.00 m = 18 m²
18.0 m²
The answer should be
1. 23 kg + 46 kg
= 69 kg
The er skould be
The answer should be
69.0cm
2. 23.0 cm + 46.0 cm = 69 cm
3. 253 m + 345.8 m = 598.8 m
The answer should be
= 21 s
The answer should be
4. 56 s-35 s
5. 56.00 km – 35.0 km= 21 km
The answer should be
6. 46 m² x 12 m
= 552 m3
The answer should be
The answer should be
7. 3.24 cm x 5.63 cm³ = 18.2412 cm*
8 (2.355 m + 2.645 m) x 10.00 m = 50 m²
The answer should be
654 mm3 + 32 m = 20.4375 mm²
The answer should be
9
10. .024 g x .063 g
= 1.512 x 10°g²
The answer should be
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education

Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning

Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY