2.2.77 f(x + h) – f(x) Find the difference quotient of f; that is, find h+ 0, for the following function. Be sure to simplify. h f(x) = x2 - 4x + 2 f(x + h) – f(x) (Simplify your answer.) h

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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Find the difference quotient of f; that is, find (f(x+h)-f(x))/(h),h=0
for the following function. Be sure to simplify.

f(h)=x^(2)-4x+2

 

(f(x+h)-f(x))/(h)=

### Calculus: Difference Quotient

#### Example Problem: 2.2.77

Find the difference quotient of \( f \); that is, find \(\frac{f(x + h) - f(x)}{h}\), \( h \neq 0 \), for the following function. Be sure to simplify.

\[ f(x) = x^2 - 4x + 2 \]

\[ \frac{f(x + h) - f(x)}{h} = \boxed{(Simplify your answer.)} \]

**Explanation:**

In calculus, the difference quotient is a measure of how a function changes as its input changes. It is given by the formula:

\[ \frac{f(x + h) - f(x)}{h} \]

where \( h \) is a small change in \( x \), and \( h \neq 0 \). The function \( f(x) \) in this problem is a quadratic function defined as:

\[ f(x) = x^2 - 4x + 2 \]

To find the difference quotient, follow these steps:

1. **Substitute \( x + h \) into the function \( f(x) \):**
\[ f(x + h) = (x + h)^2 - 4(x + h) + 2 \]

2. **Expand and simplify:**
\[ (x + h)^2 - 4(x + h) + 2 = x^2 + 2xh + h^2 - 4x - 4h + 2 \]

3. **Subtract \( f(x) \) from \( f(x + h) \):**
\[ (x^2 + 2xh + h^2 - 4x - 4h + 2) - (x^2 - 4x + 2) \]

4. **Combine like terms:**
\[ x^2 + 2xh + h^2 - 4x - 4h + 2 - x^2 + 4x - 2 = 2xh + h^2 - 4h \]

5. **Factor out \( h \) from the expression:**
\[ 2xh + h^2 - 4h = h(2x + h - 4) \]

6. **Divide by \( h \) (the difference quotient):**
\[ \frac{h
Transcribed Image Text:### Calculus: Difference Quotient #### Example Problem: 2.2.77 Find the difference quotient of \( f \); that is, find \(\frac{f(x + h) - f(x)}{h}\), \( h \neq 0 \), for the following function. Be sure to simplify. \[ f(x) = x^2 - 4x + 2 \] \[ \frac{f(x + h) - f(x)}{h} = \boxed{(Simplify your answer.)} \] **Explanation:** In calculus, the difference quotient is a measure of how a function changes as its input changes. It is given by the formula: \[ \frac{f(x + h) - f(x)}{h} \] where \( h \) is a small change in \( x \), and \( h \neq 0 \). The function \( f(x) \) in this problem is a quadratic function defined as: \[ f(x) = x^2 - 4x + 2 \] To find the difference quotient, follow these steps: 1. **Substitute \( x + h \) into the function \( f(x) \):** \[ f(x + h) = (x + h)^2 - 4(x + h) + 2 \] 2. **Expand and simplify:** \[ (x + h)^2 - 4(x + h) + 2 = x^2 + 2xh + h^2 - 4x - 4h + 2 \] 3. **Subtract \( f(x) \) from \( f(x + h) \):** \[ (x^2 + 2xh + h^2 - 4x - 4h + 2) - (x^2 - 4x + 2) \] 4. **Combine like terms:** \[ x^2 + 2xh + h^2 - 4x - 4h + 2 - x^2 + 4x - 2 = 2xh + h^2 - 4h \] 5. **Factor out \( h \) from the expression:** \[ 2xh + h^2 - 4h = h(2x + h - 4) \] 6. **Divide by \( h \) (the difference quotient):** \[ \frac{h
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