2.12x₁2.12x₂ +51.3x3 + 100x4 = π, 0.333x₁ -0.333x₂ - 12.2x3 + 19.7x4 = √√2, 6.19x₁ + 8.20x2 1.00x32.01x4 = 0, -5.73x₁ +6.12x2 + X3 - X4 = -1.
2.12x₁2.12x₂ +51.3x3 + 100x4 = π, 0.333x₁ -0.333x₂ - 12.2x3 + 19.7x4 = √√2, 6.19x₁ + 8.20x2 1.00x32.01x4 = 0, -5.73x₁ +6.12x2 + X3 - X4 = -1.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Gaussian elimination with partial pivoting.
![C. 2.12x₁2.12x₂
0.333x₁0.333x₂
+51.3x3 + 100x4 = π,
- 12.2x3 + 19.7x4 = √√2,
1.00x32.01x4 = 0,
6.19x1 +8.20x2
-5.73x₁ + 6.12x₂ +
X3 -
Actual solution [0.0998,-0.0683,-0.0363, 0.0465].
-1.
X4 = -](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7186d64-925e-49f0-bec9-99e212bea2ee%2F37c0d72f-a7e8-4325-9212-bb7d79c8ddb2%2Frddvx6u_processed.png&w=3840&q=75)
Transcribed Image Text:C. 2.12x₁2.12x₂
0.333x₁0.333x₂
+51.3x3 + 100x4 = π,
- 12.2x3 + 19.7x4 = √√2,
1.00x32.01x4 = 0,
6.19x1 +8.20x2
-5.73x₁ + 6.12x₂ +
X3 -
Actual solution [0.0998,-0.0683,-0.0363, 0.0465].
-1.
X4 = -
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