2.1 Problem Formulation Recall that Binary subtraction appeals to binary addition only, thus it suffices to only translate the input of B = (B3, B2, B1, B₁) into corresponding 2's complement form before feeding it into the 4-bit adder. Let us denote G (G3, G2, G₁, Go) as the input of the 4-bit adder. Complete the truth-table: M| B3 B₂ B₁ Bo G3 G₂ G₁ Go 0 X XXX B3 B₂ B₁ Bo 0000000 0 1

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2.1 Problem Formulation
Recall that Binary subtraction appeals to binary addition only, thus it suffices to only translate the input of B =
(B3, B2, B₁, Bo) into corresponding 2's complement form before feeding it into the 4-bit adder. Let us denote G =
(G3, G2, G₁, Go) as the input of the 4-bit adder. Complete the truth-table:
M B3 B2 B₁ Bo G3 G₂ G₁ Go
0
X X X X B3 B2 B₁ Bo
0
0 0 0
1
1 1
0 0 0 0
00011
100 10
1
1
1 0011
1 0 1 0 0
10101|
101 10
1 0111
1 1000
1
1001
1 1010
1
1
0 1 1
1 1 100
1
1101
11110
11111
2.2 Logic Minimisation
Using any means of logic minimization, either K-map or Boolean algebra or even by observation, rewrite the
four Boolean functions of (G3, G2, G₁, Go) using the inputs (M, B3, B2, B1, Bo).
2.3 Design
Complete the following schematic using external XOR gates only. Note that the A's and B's follow the
specification of the 74LS83 IC data sheet; and they do not necessarily mean our generic system input.
A3
A₂
A₁
Ao
B3
B2
B1
Bo
74LS83
Cin
Cout
S3
S₂
S₁
So
2 / 3
Transcribed Image Text:2.1 Problem Formulation Recall that Binary subtraction appeals to binary addition only, thus it suffices to only translate the input of B = (B3, B2, B₁, Bo) into corresponding 2's complement form before feeding it into the 4-bit adder. Let us denote G = (G3, G2, G₁, Go) as the input of the 4-bit adder. Complete the truth-table: M B3 B2 B₁ Bo G3 G₂ G₁ Go 0 X X X X B3 B2 B₁ Bo 0 0 0 0 1 1 1 0 0 0 0 00011 100 10 1 1 1 0011 1 0 1 0 0 10101| 101 10 1 0111 1 1000 1 1001 1 1010 1 1 0 1 1 1 1 100 1 1101 11110 11111 2.2 Logic Minimisation Using any means of logic minimization, either K-map or Boolean algebra or even by observation, rewrite the four Boolean functions of (G3, G2, G₁, Go) using the inputs (M, B3, B2, B1, Bo). 2.3 Design Complete the following schematic using external XOR gates only. Note that the A's and B's follow the specification of the 74LS83 IC data sheet; and they do not necessarily mean our generic system input. A3 A₂ A₁ Ao B3 B2 B1 Bo 74LS83 Cin Cout S3 S₂ S₁ So 2 / 3
1.
Introduction
In this lab, we are going to design a more complicated combinational logic. The designed circuit will be
simulated using the OrCAD capture and PSpice.
4-bit adder/subtractor
The function of the circuit can be described by the equation:
(A + B,
if M
A
B,
if M
In other words, this system is to add or subtract two 4-bit binary numbers A and B.
Y
The system will have 9 input pins:
A = (A3, A2, A1, A0),
B = (B3, B2, B₁, Bo), and
M (mode selection).
The system will have 5 output pins:
S = (S3, S2, S1, So), and
Co (carry out)
-
-
If the input M (Mode select) is 0, then the circuit will give the sum Y= A + B. If M is 1, then the circuit will
perform the operation Y = A - B. The result of the operation in both cases will appear in the output S and the
output carry (Cout).
We assume A3, B3, and S3 are the most significant bits (MSB).
0;
1.
In this section, you are only allowed to use the following components:
4 x 2 input XOR gate (7486)
1 x 4-bit binary adder (7483A)
9 x input STIM1 Ports (one for each input pin)
5 x output Hierarchical Ports (one for each output pin)
Transcribed Image Text:1. Introduction In this lab, we are going to design a more complicated combinational logic. The designed circuit will be simulated using the OrCAD capture and PSpice. 4-bit adder/subtractor The function of the circuit can be described by the equation: (A + B, if M A B, if M In other words, this system is to add or subtract two 4-bit binary numbers A and B. Y The system will have 9 input pins: A = (A3, A2, A1, A0), B = (B3, B2, B₁, Bo), and M (mode selection). The system will have 5 output pins: S = (S3, S2, S1, So), and Co (carry out) - - If the input M (Mode select) is 0, then the circuit will give the sum Y= A + B. If M is 1, then the circuit will perform the operation Y = A - B. The result of the operation in both cases will appear in the output S and the output carry (Cout). We assume A3, B3, and S3 are the most significant bits (MSB). 0; 1. In this section, you are only allowed to use the following components: 4 x 2 input XOR gate (7486) 1 x 4-bit binary adder (7483A) 9 x input STIM1 Ports (one for each input pin) 5 x output Hierarchical Ports (one for each output pin)
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