2.1 Problem FormulationRecall that Binary subtraction appeals to binary addition only, thus it suffices to only translate the input of B =(B3, B2, B₁, Bo) into corresponding 2's complement form before feeding it into the 4-bit adder. Let us denote G =(G3, G2, G₁, Go) as the input of the 4-bit adder. Complete the truth-table:M B3 B2 B₁ Bo G3 G₂ G₁ Go0X X X X B3 B2 B₁ Bo00 0 011 10 0 0 000011100 10111 00111 0 1 0 010101|101 101 01111 1000110011 1010110 1 11 1 1001110111110111112.2 Logic MinimisationUsing any means of logic minimization, either K-map or Boolean algebra or even by observation, rewrite thefour Boolean functions of (G3, G2, G₁, Go) using the inputs (M, B3, B2, B1, Bo).2.3 DesignComplete the following schematic using external XOR gates only. Note that the A's and B's follow thespecification of the 74LS83 IC data sheet; and they do not necessarily mean our generic system input.A3A₂A₁AoB3B2B1Bo74LS83CinCoutS3S₂S₁So2 / 3 1.IntroductionIn this lab, we are going to design a more complicated combinational logic. The designed circuit will besimulated using the OrCAD capture and PSpice.4-bit adder/subtractorThe function of the circuit can be described by the equation:(A + B,if MAB,if MIn other words, this system is to add or subtract two 4-bit binary numbers A and B.YThe system will have 9 input pins:A = (A3, A2, A1, A0),B = (B3, B2, B₁, Bo), andM (mode selection).The system will have 5 output pins:S = (S3, S2, S1, So), andCo (carry out)--If the input M (Mode select) is 0, then the circuit will give the sum Y= A + B. If M is 1, then the circuit willperform the operation Y = A - B. The result of the operation in both cases will appear in the output S and theoutput carry (Cout).We assume A3, B3, and S3 are the most significant bits (MSB).0;1.In this section, you are only allowed to use the following components:4 x 2 input XOR gate (7486)1 x 4-bit binary adder (7483A)9 x input STIM1 Ports (one for each input pin)5 x output Hierarchical Ports (one for each output pin)

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2.1 Problem Formulation Recall that Binary subtraction appeals to binary addition only, thus it suffices to only translate the input of B = (B3, B2, B1, B₁) into corresponding 2's complement form before feeding it into the 4-bit adder. Let us denote G (G3, G2, G₁, Go) as the input of the 4-bit adder. Complete the truth-table: M| B3 B₂ B₁ Bo G3 G₂ G₁ Go 0 X XXX B3 B₂ B₁ Bo 0000000 0 1

2.1 Problem Formulation Recall that Binary subtraction appeals to binary addition only, thus it suffices to only translate the input of B = (B3, B2, B1, B₁) into corresponding 2's complement form before feeding it into the 4-bit adder. Let us denote G (G3, G2, G₁, Go) as the input of the 4-bit adder. Complete the truth-table: M| B3 B₂ B₁ Bo G3 G₂ G₁ Go 0 X XXX B3 B₂ B₁ Bo 0000000 0 1

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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