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(2.1) (e³, 0) A curve passes through the point and the slope of the normal line at each point (x.y) is equal to re . In the process of finding the equation of such a curve, one step in developing the solution is as follows: dz O a) 1 dy eby O b) – In |a|: 1 by + C, donde C e R e Oc) In = e -ôy + C, donde CE R. dy O d) -6y = ce -- da

(2.1) (e³, 0) A curve passes through the point and the slope of the normal line at each point (x.y) is equal to re . In the process of finding the equation of such a curve, one step in developing the solution is as follows: dz O a) 1 dy eby O b) – In |a|: 1 by + C, donde C e R e Oc) In = e -ôy + C, donde CE R. dy O d) -6y = ce -- da

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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(2.1) (e³, 0) A curve passes through the point and the slope of the normal line at each point (x.y) is equal to re . In the process of finding the equation of such a curve, one step in developing the solution is as follows: dz O a) 1 dy eby O b) – In |a|: 1 by + C, donde C e R e Oc) In = e -ôy + C, donde CE R. dy O d) -6y = ce -- da
Transcribed Image Text:(2.1) (e³, 0) A curve passes through the point and the slope of the normal line at each point (x.y) is equal to re . In the process of finding the equation of such a curve, one step in developing the solution is as follows: dz O a) 1 dy eby O b) – In |a|: 1 by + C, donde C e R e Oc) In = e -ôy + C, donde CE R. dy O d) -6y = ce -- da
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