2.1 Consider a linear chain in which alternate ions have masses M₁ and M2, and only neares neighbors interact. (i) K K a/2 a K ww w² (k)= M₁ K Show that the dispersion relation for normal modes is: K wow M₂ 2 1 1 1 1 4 ka = K < (+) ± √(-+)²-, M₂ sin (22) +K += M₁ M₂ M₂ M₁M₂ Where, K is the spring constant, and a, is the size of the unit cell (so the spacing between atoms is a/2). Derive an expression for the group velocity vg as a function of k. (iii) Use the results of part (ii), to evaluate vg for k at the Brillouin Zone boundary.[k = + and briefly discuss the physical significance of this Brillouin Zone boundary group
2.1 Consider a linear chain in which alternate ions have masses M₁ and M2, and only neares neighbors interact. (i) K K a/2 a K ww w² (k)= M₁ K Show that the dispersion relation for normal modes is: K wow M₂ 2 1 1 1 1 4 ka = K < (+) ± √(-+)²-, M₂ sin (22) +K += M₁ M₂ M₂ M₁M₂ Where, K is the spring constant, and a, is the size of the unit cell (so the spacing between atoms is a/2). Derive an expression for the group velocity vg as a function of k. (iii) Use the results of part (ii), to evaluate vg for k at the Brillouin Zone boundary.[k = + and briefly discuss the physical significance of this Brillouin Zone boundary group
Related questions
Question

Transcribed Image Text:2.1 Consider a linear chain in which alternate ions have masses M₁ and M2, and only nearest
neighbors interact.
(i)
K
K
www
a/2
a
w²(k) = K
K
M₁
K
Show that the dispersion relation for normal modes is:
K
Ow
M₂
(+) ± √(-+)-M₁M₂ Sin (7)
Where, K is the spring constant, and a, is the size of the unit cell (so the spacing
between atoms is a/2).
(ii) Derive an expression for the group velocity vg as a function of k.
H
(iii)
Use the results of part (ii), to evaluate và for k at the Brillouin Zone boundary, [k
and briefly discuss the physical significance of this Brillouin Zone boundary group
volocity (Specifically what do you say about propagation of longitudinal waves in the
(
±
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 4 images
