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XC

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2.05F
Solve for XC in this circuit
27k ohm
25.89k ohm
10k ohm
5k ohm
Transcribed Image Text:2.05F Solve for XC in this circuit 27k ohm 25.89k ohm 10k ohm 5k ohm
Expert Solution
Step 1

Here the circuit consists of an alternating voltage supplier and a capacitor, Xc of a capacitor depicts the capacitive impedance in the circuit

now Xc is evaluated using the formula

Xc=1jωCwhere j=-1 is the imaginary numberXc=1ωC       =12πfC

here f is the frequency of the alternating voltage and C is the capacitance of the capacitor, ω being the angular frequency of the alternating voltage, ω=2πf

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