2.04 s = 20.4 m 4a= -9.80 m/s? ta = 0 "a= 20.0 m/s dye = -9.80 m/s² © te = 4.08 s 'e = 0 ye = -20.0 m/s de = -9.80 m/s? O lo = 5.00 s -22.5 m 50.0 m -29.0 m/s 40=-9.80 m/s? Figure 2.14 (Example 2.10) Position, velocity, and acceleration values at various times for a freely falling stone thrown initially upward with a velocity ", = 20.0 m/s. Many of the quantities in the labels for points in the motion of the stone are calculated in the te = 5.83 s -50.0 m example. Can you verify the other val- ues that are not? Vye= -37.1 m/s dye = -9.80 m/s?
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
A stone thrown from the top of a building is given an initial velocity of 20.0 m/s straight upward. The stone is launched 50.0 m above the ground, and the stone just misses the edge of the roof on its way down as shown.
(A) Using tⒶ = 0 as the time the stone leaves the thrower’s hand at position Ⓐ, determine the time at which the stone reaches its maximum height.
(B) Find the maximum height of the stone. (C) Determine the velocity of the stone when it returns to the height from which it was thrown. (D) Find the velocity and position of the stone at t = 5.00 s.
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