2. Zn +_HCI →__ZnCl2 + _H2 When 5.00g of zinc metal reacts with excess hydrochloric acid, how many grams of zinc chloride will be produced?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Balance the following chemical reaction, and complete the stoichiometry problem:

 

### Stoichiometry Problem

**Problem Statement:**

2. __Zn + __HCl → __ZnCl₂ + __H₂  
When 5.00g of zinc metal reacts with excess hydrochloric acid, how many grams of zinc chloride will be produced?

**Explanation:**

This question involves a chemical reaction between zinc metal (Zn) and hydrochloric acid (HCl). The reaction that takes place is written in an unbalanced equation format:

\[ \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \]

To solve this problem, one would need to balance the chemical equation first and then use stoichiometry to find out how many grams of zinc chloride (ZnCl₂) will be produced from 5.00 grams of zinc reacting with an excess of hydrochloric acid. 

1. **Balance the Equation:**

\[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \]

2. **Calculate the molar masses:**

   - Molar mass of Zn = 65.38 g/mol
   - Molar mass of ZnCl₂ = 136.30 g/mol 

3. **Convert the mass of Zn to moles:**

\[ \frac{5.00 \, \text{g Zn}}{65.38 \, \text{g/mol}} = 0.0765 \, \text{mol Zn} \]

4. **Use the stoichiometry of the balanced equation to find moles of ZnCl₂ produced:**

\[ \text{1 mol Zn} \rightarrow \text{1 mol ZnCl}_2 \]

So, 0.0765 mol Zn produces 0.0765 mol ZnCl₂.

5. **Convert moles of ZnCl₂ to grams:**

\[ 0.0765 \, \text{mol ZnCl}_2 \times 136.30 \, \text{g/mol} = 10.43 \, \text{g ZnCl}_2 \]

**Conclusion:**

\[ \boxed{10.43} \]

When 5.00 grams of zinc metal reacts with excess hydrochloric acid, 10.43 grams of zinc chloride will be produced.
Transcribed Image Text:### Stoichiometry Problem **Problem Statement:** 2. __Zn + __HCl → __ZnCl₂ + __H₂ When 5.00g of zinc metal reacts with excess hydrochloric acid, how many grams of zinc chloride will be produced? **Explanation:** This question involves a chemical reaction between zinc metal (Zn) and hydrochloric acid (HCl). The reaction that takes place is written in an unbalanced equation format: \[ \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \] To solve this problem, one would need to balance the chemical equation first and then use stoichiometry to find out how many grams of zinc chloride (ZnCl₂) will be produced from 5.00 grams of zinc reacting with an excess of hydrochloric acid. 1. **Balance the Equation:** \[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \] 2. **Calculate the molar masses:** - Molar mass of Zn = 65.38 g/mol - Molar mass of ZnCl₂ = 136.30 g/mol 3. **Convert the mass of Zn to moles:** \[ \frac{5.00 \, \text{g Zn}}{65.38 \, \text{g/mol}} = 0.0765 \, \text{mol Zn} \] 4. **Use the stoichiometry of the balanced equation to find moles of ZnCl₂ produced:** \[ \text{1 mol Zn} \rightarrow \text{1 mol ZnCl}_2 \] So, 0.0765 mol Zn produces 0.0765 mol ZnCl₂. 5. **Convert moles of ZnCl₂ to grams:** \[ 0.0765 \, \text{mol ZnCl}_2 \times 136.30 \, \text{g/mol} = 10.43 \, \text{g ZnCl}_2 \] **Conclusion:** \[ \boxed{10.43} \] When 5.00 grams of zinc metal reacts with excess hydrochloric acid, 10.43 grams of zinc chloride will be produced.
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