2. Your friend drives the small arc (w) at 7 m/s, then accelerates on the lower straightaway (X) from 7 m/s to 13 m/s, which takes 2 seconds, drives the large arc (Y) at a constant speed of 13 m/s, and then slows back down on the top straightaway (Z) from 13 m/s to 7 m/s in 2 seconds. W Y Draw arrows indicating the direction of the acceleration at each point with larger arrows where the acceleration is larger. Determine the magnitude of the acceleration at the four points. W: X: Y: Z:

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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2. Your friend drives the small arc (W) at 7
m/s, then accelerates on the lower
straightaway (X) from 7 m/s to 13 m/s,
which takes 2 seconds, drives the large arc
(Y) at a constant speed of 13 m/s, and then
slows back down on the top straightaway
(Z) from 13 m/s to 7 m/s in 2 seconds.
Y
Draw arrows indicating the direction of the
acceleration at each point with larger
arrows where the acceleration is larger.
Determine the magnitude of the
acceleration at the four points.
W:
X:
Y:
Z:
Transcribed Image Text:2. Your friend drives the small arc (W) at 7 m/s, then accelerates on the lower straightaway (X) from 7 m/s to 13 m/s, which takes 2 seconds, drives the large arc (Y) at a constant speed of 13 m/s, and then slows back down on the top straightaway (Z) from 13 m/s to 7 m/s in 2 seconds. Y Draw arrows indicating the direction of the acceleration at each point with larger arrows where the acceleration is larger. Determine the magnitude of the acceleration at the four points. W: X: Y: Z:
Expert Solution
Step 1

At W, velocity is constant and equals to 7m/s. So acceleration is 0.

 At Y, acceleration = (change in velocity)/(time taken) = (13m/s-7m/s)/(2s) =3m/s2

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